不可以!(快考试了做些简单题)
不可以!
时间限制:1000 ms | 内存限制:65535 KB
- 描述
-
判断:两个数x、y的正负性。
要求:不可以使用比较运算符,即"<",">","<=",">=","==","!="。
- 输入
- 有多组数据,每组数据占一行,每一行两个数x,y。
x、y保证在int范围内。 - 输出
- 每组数据输出占一行。
如果两个数是一正一负,输出"Signs are opposite"
如果是同为正或同为负,输出"Signs are not opposot"
如果无法确定,输出"Signs can't be sure"
输出不包括引号 - 样例输入
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1 1 -1 1
- 样例输出
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Signs are not opposot Signs are opposite
int:1 #include <iostream> 2 #include <cstdio> 3 #include <cstdlib> 4 using namespace std; 5 int main() 6 { 7 int n,m; 8 while(cin>>n>>m) 9 { 10 if(!(n*m)) 11 cout<<"Signs can't be sure\n"; 12 else if(!(m*n+abs(m*n))) 13 cout<<"Signs are opposite\n"; 14 else 15 cout<<"Signs are not opposot\n"; 16 } 17 }
string:
1 #include <iostream> 2 #include <cstdio> 3 #include <cstdlib> 4 using namespace std; 5 int main() 6 { 7 char n[15],m[15]; 8 while(cin>>n>>m) 9 { 10 if(n[0]=='0'||m[0]=='0') 11 cout<<"Signs can't be sure\n"; 12 else if((n[0]!='-'&&m[0]=='-')||(n[0]=='-'&&m[0]!='-')) 13 cout<<"Signs are opposite\n"; 14 else 15 cout<<"Signs are not opposot\n"; 16 } 17 }