winfrom实现简单计算器V2版本
前面，使用winform实现了个简单的计算器，今天，再来给大家看一个稍微复杂点的计算器，效果图如下：
包括归零，退格，加减乘除都已经实现，如果想要继续扩展的可以在稍微改改即可。
现在看看怎么实现的：
1.先从工具箱里面拉出来一个这样的窗体：
2.归零的方法：
private void qingchu_Click(object sender, EventArgs e)
{
this.lbljieguo.Text = "0";
sb = new StringBuilder("");
}
3.退格的方法：
//退格的按钮
private void tuige_Click(object sender, EventArgs e)
{
//判断当前能不能点击退格
//判断显示框是否有值，有值的话可以删除，没有值的话提示不能删除
if (this.lbljieguo.Text.Length > 0)
{
char ch = 'a'; //保存符号
//遍历字符串
foreach (char c in sb.ToString())
{
ch = c; //最后一个值放在ch里面
}
//判断最后一个是否是+-*/%
if (ch != '+')
{
//如果是，不能动num1和num2,否则可以动
if (flag == false)
{
num1 = new StringBuilder(num1.ToString().Substring(0, num1.Length - 1));
}
else
{
num2 = new StringBuilder(num2.ToString().Substring(0, num2.Length - 1));
}
}
ji = false;
this.lbljieguo.Text = sb.ToString().Substring(0, this.lbljieguo.Text.Length - 1);
sb = new StringBuilder(this.lbljieguo.Text);
}
else
{
MessageBox.Show("显示框都没有值，你删啥？", "提示信息");
}
}
4.（1 2 3 4 5 6 7 8 9 0）的点击事件：
//第一个数
StringBuilder num1 = new StringBuilder();
//第二个数
StringBuilder num2 = new StringBuilder();
//判断是否是第一次输入
bool flag = false;
//运算符
string fu = "";
//当计算完结果时，不能退格
bool ji = false;
StringBuilder sb = new StringBuilder();
//7
private void btn7_Click(object sender, EventArgs e)
{
if (flag == false)
{
num1.Append(7);
}
else
{
num2.Append(7);
}
sb.Append(7);
this.lbljieguo.Text = sb.ToString();
}
//8
private void btn8_Click(object sender, EventArgs e)
{
if (flag == false)
{
num1.Append(8);
}
else
{
num2.Append(8);
}
sb.Append(8);
this.lbljieguo.Text = sb.ToString();
}
private void btn9_Click(object sender, EventArgs e)
{
if (flag == false)
{
num1.Append(9);
}
else
{
num2.Append(9);
}
sb.Append(9);
this.lbljieguo.Text = sb.ToString();
}
private void btn4_Click(object sender, EventArgs e)
{
if (flag == false)
{
num1.Append(4);
}
else
{
num2.Append(4);
}
sb.Append(4);
this.lbljieguo.Text = sb.ToString();
}
private void btn5_Click(object sender, EventArgs e)
{
if (flag == false)
{
num1.Append(5);
}
else
{
num2.Append(5);
}
sb.Append(5);
this.lbljieguo.Text = sb.ToString();
}
private void btn6_Click(object sender, EventArgs e)
{
if (flag == false)
{
num1.Append(6);
}
else
{
num2.Append(6);
}
sb.Append(6);
this.lbljieguo.Text = sb.ToString();
}
private void btn1_Click(object sender, EventArgs e)
{
if (flag == false)
{
num1.Append(1);
}
else
{
num2.Append(1);
}
sb.Append(1);
this.lbljieguo.Text = sb.ToString();
}
private void btn2_Click(object sender, EventArgs e)
{
if (flag == false)
{
num1.Append(2);
}
else
{
num2.Append(2);
}
sb.Append(2);
this.lbljieguo.Text = sb.ToString();
}
private void btn3_Click(object sender, EventArgs e)
{
if (flag == false)
{
num1.Append(3);
}
else
{
num2.Append(3);
}
sb.Append(3);
this.lbljieguo.Text = sb.ToString();
}
private void btn0_Click(object sender, EventArgs e)
{
if (flag == false)
{
num1.Append(0);
}
else
{
num2.Append(0);
}
sb.Append(0);
this.lbljieguo.Text = sb.ToString();
}
5.加减乘除的点击事件：
private void btnchu_Click(object sender, EventArgs e)
{
flag = true;
sb.Append("/");
this.lbljieguo.Text = sb.ToString();
fu = "/";
}
private void btnyu_Click(object sender, EventArgs e)
{
flag = true;
sb.Append("%");
this.lbljieguo.Text = sb.ToString();
fu = "%";
}
private void btnjia_Click(object sender, EventArgs e)
{
flag = true;
sb.Append("+");
this.lbljieguo.Text = sb.ToString();
fu = "+";
}
private void btnjian_Click(object sender, EventArgs e)
{
flag = true;
sb.Append("-");
this.lbljieguo.Text = sb.ToString();
fu = "-";
}
private void btncheng_Click(object sender, EventArgs e)
{
flag = true;
sb.Append("*");
this.lbljieguo.Text = sb.ToString();
fu = "*";
}
6.等于的方法：
//等于的按钮
private void btndeng_Click(object sender, EventArgs e)
{
//string xianshi = sb.ToString();
switch (fu)
{
case "+":
this.lbljieguo.Text = (int.Parse(num1.ToString()) + int.Parse(num2.ToString())).ToString();
break;
case "-":
this.lbljieguo.Text = (int.Parse(num1.ToString()) - int.Parse(num2.ToString())).ToString();
break;
case "*":
this.lbljieguo.Text = (int.Parse(num1.ToString()) * int.Parse(num2.ToString())).ToString();
break;
case "/":
this.lbljieguo.Text = (int.Parse(num1.ToString()) / int.Parse(num2.ToString())).ToString();
break;
case "%":
this.lbljieguo.Text = (int.Parse(num1.ToString()) % int.Parse(num2.ToString())).ToString();
break;
}
num1 = new StringBuilder("");
num2 = new StringBuilder("");
sb = new StringBuilder("");
flag = false;
ji = true; //显示的是结果
}
整个的实现方法以及代码都已经给出，不做伸手党，自己动脑思考思考，加油啊，在编码路上的你们~~
