关耳er  

一、Person类的编写

public class Person {
    Scanner input = new Scanner(System.in);
    String name1; // 用户姓名
    int perFist; // 用户出拳
    int comFist; // 电脑出拳
    int score1; // 用户积分
    int score2; // 对方积分
    int count; // 对战次数
    int choose; // 选择

    /**
     * 用户选择类
     */
    public void show() {
        System.out.println("出拳规则:1.剪刀2.石头3.布");
        System.out.println("请选择对方角色(1.刘备2.孙权3.曹操)");
        choose = input.nextInt();
        System.out.println("请输入您的姓名:");
        name1 = input.next();
        // 对决判断
        do {
            switch (choose) {
            case 1:
                System.out.println(name1 + "  VS" + "刘备");
                break;
            case 2:
                System.out.println(name1 + "  VS" + "孙权");
                break;
            case 3:
                System.out.println(name1 + "  VS" + "曹操");
                break;
            default:
                System.out.println("输入有误请重新输入:");
                break;
            }
        } while (choose > 3);
    }

    /**
     * 出拳循环类
     */
    public void show1() {
        System.out.println("要开始吗?(y/n)");
        char answer = input.next().charAt(0);
        if (answer == 'y') {
            System.out.println("\n请出拳:1.剪刀2.石头3.布(请输入相应数字!):");
            int perFist = input.nextInt();
            boolean chose=true;
            // 随机数的产生
            int comFist = (int) (Math.random() * 3+1);
            switch (comFist) {
            case 1:
                System.out.println("对手出拳:剪刀");
                break;
            case 2:
                System.out.println("对手出拳:石头");
                break;
            case 3:
                System.out.println("对手出拳:布");
                break;
            }
            // 判断用户与计算机的出拳结果
            if ((perFist == 1 && comFist == 1) || (perFist == 2 && comFist == 2) || (perFist == 3 && comFist == 3)) {
                System.out.println("结果:平局,真衰!\n"); // 平局
            } else if ((perFist == 1 && comFist == 3) || (perFist == 2 && comFist == 1)
                    || (perFist == 3 && comFist == 2)) {
                score1++;
                System.out.println("结果:恭喜,你赢了!"); // 用户赢
            } else {
                score2++;
                System.out.println("结果:你输了,真笨!\n"); // 计算机赢
            }
        }
    }

    /**
     * 结果类
     */
    public void show2() {
        String name2 = ""; // 定义选手名字
        System.out.println("————————————————————————————————————————————-");
        switch (choose) {
        case 1:
            name2 = "刘备";
            break;
        case 2:
            name2 = "孙权";
            break;
        case 3:
            name2 = "曹操";
            break;
        }
        System.out.println(name1 + "  VS" + name2);
        System.out.println("对战次数:" + count);
        System.out.println("\n姓名\t得分");
        System.out.println(name1 + "\t" + score1);
        System.out.println(name2 + "\t" + score2);
        if (score1 > score2) {
            System.out.println("恭喜恭喜!");
        } else {
            System.out.println("呵呵,笨笨,下次加油哦!");
        }
        System.out.println("————————————————————————————————————————————-");
    }
}

二、测试Person类

public class Test {
    /**
     * 实例化过程
     */

    public static void main(String[] args) {
        System.out.println("————————————欢迎进入游戏世界————————————");
        System.out.println("\t******************");
        System.out.println("\t**猜拳,开始**");
        System.out.println("\t******************\n");
        Scanner input = new Scanner(System.in);
        /**
         * 创建对象
         */
        Person game = new Person();
        char chioce; // 定义选择
        int count = 0; // 定义对战次数
        /**
         * 调用方法
         */
        game.show();
        do {
            /**
             * 调用方法
             */
            game.show1();
            // 判断
            System.out.println("\n是否进入下一轮?(y/n)");
            chioce = input.next().charAt(0);
            count++;
        } while (chioce == 'y');
        /**
         * 调用方法
         */
        game.show2();
    }
}

 

posted on 2018-10-15 09:41  关耳er  阅读(160)  评论(0编辑  收藏  举报