HDU 5907 Find Q（简单字符串）

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Description

Byteasar is addicted to the English letter 'q'. Now he comes across a string S consisting of lowercase English letters.

He wants to find all the continous substrings of S, which only contain the letter 'q'. But this string is really really long, so could you please write a program to help him?

Input

The first line of the input contains an integer T(1≤T≤10), denoting the number of test cases.

In each test case, there is a string S, it is guaranteed that S only contains lowercase letters and the length of S is no more than 100000.

Output

For each test case, print a line with an integer, denoting the number of continous substrings of S, which only contain the letter 'q'.

Sample Input

2
qoder 
quailtyqqq

Sample Output

1
7

思路

题意：找出SS的所有仅包含字母'q'的连续子串

只要求出每个位置能往右延伸多长即可。

 

+ View Code?

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#include<cstdio> #include<cstring> using namespace std; const int maxn = 100005; char a[maxn];   int main() {     int T;     scanf("%d",&T);     while (T--)     {         __int64 res = 0,cnt = 0;         scanf("%s",a);         int len = strlen(a);         for (int i = 0;i < len;)         {             if (a[i] == 'q')             {                 while (a[i] == 'q')                 {                     i++;                     cnt++;                 }                 res += (1+cnt)*cnt/2;                 cnt = 0;             }             else             {                 i++;             }         }         printf("%I64d\n",res);     }     return 0; }