uva10026-鞋匠的难题

题目链接 http://acm.hust.edu.cn/vjudge/problem/21234

 

解题思路

因为越晚完成，惩罚的天数越多。所以可以以 罚金/完成所需天数 从大到小排序

 

代码

#include<stdio.h>
#include<string.h>
//#define LOCAL
#define MAX_LEN 1005
struct Node {
    double t, f;
    int num;
    double a;
}task[MAX_LEN];
int n;
void Solve()
{
    for(int i=1; i<n; i++)
        for(int j=0; j<n-i; j++) {
            if(task[j].a<task[j+1].a) {
                Node temp; 
                temp = task[j]; task[j] = task[j+1]; task[j+1] = temp;
            }
        }
    for(int i=0; i<n-1; i++) printf("%d ", task[i].num); 
    printf("%d", task[n-1].num);
    printf("\n");
}
int main()
{
    #ifdef LOCAL
        freopen("data.txt", "r", stdin);
        freopen("ans.txt", "w", stdout);
    #endif
    int cases;
    scanf("%d", &cases);
    while(cases--) {
        scanf("%d", &n);
        for(int i=0; i<n; i++) {
            scanf("%lf%lf", &task[i].t, &task[i].f);
            task[i].num = i+1; task[i].a=task[i].f/task[i].t;
        }
        Solve();
        if(cases) printf("\n");
    }
    return 0;
}