Jenkins运行服务器脚本，自动打印日志捕获关键字自动退出

python update_server.py | sed '/启动成功.../q'

 

使用sed 命令搜索关键字 进行退出

或者配合 timeout  

timeout 15s python update_server.py | sed '/启动成功.../q'

这样等待15秒后会直接杀掉进程，可能会导致任务没有启动或者执行一半中断

 

 1 #!/bin/bash
 2 echo `pwd`
 3 cd app/server
 4 if [ $module == 'business' ]; then
 5     cd learn-self-business
 6     sh kill.sh
 7     sleep 3
 8     rm -f learn-self-business.jar
 9     cp ../jenkins/learn-self-business.jar .
10     sh startup.sh
11     sleep 35
12     cat nohup.out  | tail -n 100
13     echo "启动时间: `awk '/Started LearnSelfBusinessApplication in/{print $15}' ./nohup.out`"
14     start_status=`awk '/Started LearnSelfBusinessApplication in/{print ($15~/^[-]?([0-9])+[.]?([0-9])+$/)?"ok":"error"}' ./nohup.out`
15     echo $start_status
16     if [ $start_status == 'ok' ]; then
17         exit  0
18     else
19         exit 1
20     fi
21 fi

 

posted @ 2021-07-20 18:10  margo  阅读(572)  评论(0)  编辑  收藏  举报