Codeforces Gym101522 C.Cheering-字符串 (La Salle-Pui Ching Programming Challenge 培正喇沙編程挑戰賽 2017)

 

C.Cheering

 

To boost contestants' performances in the 20th La Salle - Pui Ching Programming Challenge, the organizers have bought N robots to cheer for them. Each robot is supposed to display cheering slogans, letter by letter.

Unfortunately, due to some technical reasons, the display screen of each robot can only display one fixed character. Therefore, the organizers decided to arrange the robots in a row, thus forming a string of N letters (What a waste!). All letters are in uppercase.

The two hosting schools have abbreviated names LSC and PCMS, as we all know. Which of the two names appear (as a substring) in the string more often?

Input

The first and only line of input consists of a string with N uppercase letters.

For all test cases, N ≤ 100.

Output

Let A be the number of occurrences of LSC in the given string.

Let B be the number of occurrences of PCMS in the given string.

If A > B, output LSC.

If A < B, output PCMS.

If A = B, output Tie.

Example

Input
GOLSC
Output
LSC
Input
PCMSISTHEBEST
Output
PCMS
Input
PCMSWILLNEVERBEATLSC
Output
Tie
Input
ADDOILEVERYONE
Output
Tie


代码:

 1 #include<iostream>
 2 #include<cstring>
 3 #include<cstdio>
 4 #include<cmath>
 5 #include<algorithm>
 6 using namespace std;
 7 const int N=1e5+10;
 8 char s[N];
 9 int main(){
10     memset(s,0,sizeof(s));
11     while(~scanf("%s",s)){
12         int len=strlen(s);
13         int num1=0,num2=0;
14         for(int i=0;i<len;i++){
15             if(s[i]=='L'){
16                 if(s[i+1]=='S'&&s[i+2]=='C'&&i+2<len)num1++;
17             }
18             if(s[i]=='P'){
19                 if(s[i+1]=='C'&&s[i+2]=='M'&&s[i+3]=='S'&&i+3<len)num2++;
20             }
21         }
22         if(num1>num2)printf("LSC\n");
23         else if(num1<num2)printf("PCMS\n");
24         else printf("Tie\n");
25     }
26     return 0;
27 }

 

 

 

 

 

 

 

 

posted @ 2017-12-17 20:40  ZERO-  阅读(372)  评论(0编辑  收藏  举报