查找数组中的元素

查找数组中的元素

1.输入数组并输入六个元素，查找数组中的元素伪代码

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Integer number[6]
Set position to 0
Set found to FALSE
WHILE(position < 6 AND found is FALSE)
  IF(number[poision] equals searchltem
    Set found to TURE
  ELSE
    Set position to position + 1
PRINT found

2.测试

这是C语言代码：

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#include <stdio.h>

int main() 
{
	int list[] = {60,75,95,80,65,90},num,count = 0;
	scanf("%d",&num);
	for(;count <= 5;)
	{
		if(num != list[count])
		{
			count++;
			if(count == 6)
				printf("没找到"); 
		}
		else
		{
			printf("找到"); 
			count = 6;	//强制跳出循环 
		}
	}
	return 0;
 } 

测试结果：