Instant Complexity (模拟)

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void loop(int *ans, char *lpNum)
{
    char s[10], loopNum[10] = {0};
    int i,x;
    while(scanf("%s", s) && s[0] != 'E')
    {
        if(s[0] == 'L')
        {
            int *tmp = new int[11];
            memset(tmp, 0, 11*sizeof(int));

            scanf("%s", loopNum);
            loop(tmp, loopNum);
            for(i = 0; i <= 10; i++)
                ans[i] += tmp[i];
        }
        else if(s[0] == 'O')
        {
            scanf("%d", &x);
            ans[0] += x;
        }
    }
    if(lpNum[0] == 'n')
    {
        for(i = 10; i > 0; i--)
            ans[i] = ans[i-1];
        ans[0] = 0;
    }
    else
    {
        x = atoi(lpNum);
        for(i = 0; i <= 10; i++)
            ans[i] *= x;
    }
}
int main()
{
    int t,ans[11],item;
    scanf("%d", &t);
    for(item = 1; item <= t; item++)
    {
        memset(ans, 0, sizeof(ans));
        scanf("%*s");
        loop(ans, "1");
        printf("Program #%d\nRuntime = ", item);
        bool first = 1;
        for(int i = 10; i >= 0; i--)
        {
            if(ans[i] == 0)continue;
            if(i == 0)printf("%s%d", first ? "" : "+", ans[0]);
            else if(ans[i] == 1)
                printf("%sn", first ? "" : "+");
            else if(ans[i] > 1)
                printf("%s%d*n", first ? "" : "+", ans[i]);
            if(i > 1)printf("^%d", i);
            first = 0;
        }
        if(first)printf("0");
        printf("\n\n");
    }
    return 0;
}