模板 - Treap
来自这个神仙的https://www.luogu.org/space/show?uid=56230
终于明白了Treap,不知道是因为有了足够的积累了吗?
#include<bits/stdc++.h>
typedef long long ll;
using namespace std;
const int MAXN = 1000000;
int na;
int ch[MAXN + 5][2];
int val[MAXN + 5], dat[MAXN + 5];
int siz[MAXN + 5], cnt[MAXN + 5];
int tot, root;
inline void Init() {
tot = 0;
root = 0;
}
inline int NewNode(int v) {
val[++tot] = v, dat[tot] = rand();
ch[tot][0] = ch[tot][1] = 0;
siz[tot] = 1, cnt[tot] = 1;
return tot;
}
inline void PushUp(int id) {
siz[id] = siz[ch[id][0]] + siz[ch[id][1]] + cnt[id];
}
inline void Rotate(int &id, int d) {
int temp = ch[id][d ^ 1];
ch[id][d ^ 1] = ch[temp][d];
ch[temp][d] = id;
id = temp;
PushUp(ch[id][d]), PushUp(id);
}
inline void Insert(int &id, int v) {
if(!id)
id = NewNode(v);
else {
if(v == val[id])
++cnt[id];
else {
int d = v < val[id] ? 0 : 1;
Insert(ch[id][d], v);
if(dat[id] < dat[ch[id][d]])
Rotate(id, d ^ 1);
}
PushUp(id);
}
}
void Remove(int &id, int v) {
if(!id)
return;
else {
if(v == val[id]) {
if(cnt[id] > 1) {
cnt[id]--;
PushUp(id);
} else if(ch[id][0] || ch[id][1]) {
if(!ch[id][1] || dat[ch[id][0]] > dat[ch[id][1]])
Rotate(id, 1), Remove(ch[id][1], v);
else
Rotate(id, 0), Remove(ch[id][0], v);
PushUp(id);
} else
id = 0;
} else {
v < val[id] ? Remove(ch[id][0], v) : Remove(ch[id][1], v);
PushUp(id);
}
}
}
int GetRank(int id, int v) {
if(!id)
return 0;
else {
if(v == val[id])
return siz[ch[id][0]] + 1;
else if(v < val[id])
return GetRank(ch[id][0], v);
else
return siz[ch[id][0]] + cnt[id] + GetRank(ch[id][1], v);
}
}
int GetValue(int id, int rk) {
if(!id)
return -1;
else {
if(rk <= siz[ch[id][0]])
return GetValue(ch[id][0], rk);
else if(rk <= siz[ch[id][0]] + cnt[id])
return val[id];
else
return GetValue(ch[id][1], rk - siz[ch[id][0]] - cnt[id]);
}
}
int GetPrev(int v) {
int id = root, prev = -1;
while(id) {
if(val[id] < v)
prev = val[id], id = ch[id][1];
else
id = ch[id][0];
}
return prev;
}
int GetNext(int v) {
int id = root, next = -1;
while(id) {
if(val[id] > v)
next = val[id], id = ch[id][0];
else
id = ch[id][1];
}
return next;
}
int main() {
#ifdef Yinku
freopen("Yinku.in", "r", stdin);
#endif // Yinku
init();
int ops;
scanf("%d", &ops);
for(int i = 1; i <= ops; i++) {
int op, x;
scanf("%d%d", &op, &x);
if(op == 1)
Insert(root, x);
else if(op == 2)
Remove(root, x);
else if(op == 3)
printf("%d\n", GetRank(root, x));
else if(op == 4)
printf("%d\n", GetValue(root, x));
else if(op == 5)
printf("%d\n", GetPrev(x));
else if(op == 6)
printf("%d\n", GetNext(x));
}
return 0;
}
那么就再也不需要什么对顶堆了,平衡树最多也就浪费一点空间。
https://www.luogu.org/problem/P3871
https://www.luogu.org/problem/P1801
所以说类似找排名的思想,可以找出树中的前k大的和,前k小的和,或者奇奇怪怪的其他值。也可以像之前那样加入限定,找小于v的至多k个和,每找一个还减掉一个v,总之非常灵活。
下面是找前k小的和的办法。
const int MAXN = 200005;
int ch[MAXN][2];
int val[MAXN], dat[MAXN];
ll siz[MAXN], cnt[MAXN];
ll sum[MAXN];
int tot, root;
inline void Init() {
tot = 0;
root = 0;
}
inline int NewNode(int v, ll num) {
ch[++tot][0] = ch[tot][1] = 0;
val[tot] = v, dat[tot] = rand();
siz[tot] = cnt[tot] = num;
sum[tot] = 1ll * val[tot] * cnt[tot];
return tot;
}
inline void PushUp(int id) {
siz[id] = siz[ch[id][0]] + siz[ch[id][1]] + cnt[id];
sum[id] = sum[ch[id][0]] + sum[ch[id][1]] + 1ll * val[id] * cnt[id];
}
inline void Rotate(int &id, int d) {
int temp = ch[id][d ^ 1];
ch[id][d ^ 1] = ch[temp][d];
ch[temp][d] = id;
id = temp;
PushUp(ch[id][d]), PushUp(id);
}
inline void Insert(int &id, int v, ll num) {
if(!id)
id = NewNode(v, num);
else {
if(v == val[id])
cnt[id] += num;
else {
int d = v < val[id] ? 0 : 1;
Insert(ch[id][d], v, num);
if(dat[id] < dat[ch[id][d]])
Rotate(id, d ^ 1);
}
PushUp(id);
}
}
ll GetSum(int id, ll k) {
if(!id||k<=0)
return 0;
else {
if(k >= siz[ch[id][0]] + cnt[id])
return GetSum(ch[id][1], k - siz[ch[id][0]] - cnt[id]) + sum[ch[id][0]] + 1ll * val[id] * cnt[id];
else if(k >= siz[ch[id][0]])
return sum[ch[id][0]] + 1ll * val[id] * (k - siz[ch[id][0]]);
else
return GetSum(ch[id][0], k);
}
}