Python链表成对调换
1->2->3->4 转换成 2->1->4->3
class ListNode: def __init__(self, x): self.val = x self.next = None class Solution: # @param a ListNode # @return a ListNode def swapPairs(self, head): if head != None and head.next != None: next = head.next head.next = self.swapPairs(next.next) next.next = head return next return head
卡卡,你好吗