Remote小Demo
2015-05-21 21:00 Yang-Onion 阅读(217) 评论(0) 编辑 收藏 举报Demo基于http://www.cnblogs.com/zhili/p/NETRemoting.html
RemotingObj
using System; using System.Collections.Generic; using System.Linq; using System.Runtime.Remoting.Metadata; using System.Text; using System.Threading.Tasks; namespace RemotingServer { public class RemotingObject:MarshalByRefObject { public int TestTcpAdd(int first,int second) { return first + second; } public int TestHttpMinus(int first,int second) { return first - second; } [SoapMethod(XmlNamespace = "RemotingServer", SoapAction = "RemotingServer#TestMultiIpc")] public int TestMultiIpc(int first, int second) { return first*second; } } }
RemotingServer
using System; using System.Collections.Generic; using System.Linq; using System.Runtime.Remoting; using System.Runtime.Remoting.Channels; using System.Runtime.Remoting.Channels.Http; using System.Runtime.Remoting.Channels.Ipc; using System.Runtime.Remoting.Channels.Tcp; using System.Text; using System.Threading.Tasks; namespace RemotingServer { class Program { static void Main(string[] args) { TcpChannel tcpChannel = new TcpChannel(2046); HttpChannel httpChannel = new HttpChannel(9001); IpcChannel ipcChannel = new IpcChannel("IpcTest"); ChannelServices.RegisterChannel(tcpChannel,false); ChannelServices.RegisterChannel(httpChannel,false); ChannelServices.RegisterChannel(ipcChannel,false); Console.WriteLine("The name of the Tcp Channel:{0}",tcpChannel.ChannelName); Console.WriteLine("The priority of the Tcp Channel:{0}",tcpChannel.ChannelPriority); Console.WriteLine("The name of the Http Channel:{0}",httpChannel.ChannelName); Console.WriteLine("The priority of the Http Channel:{0}",httpChannel.ChannelPriority); Console.WriteLine("The name of IPC Channel :{0}",ipcChannel.ChannelName); Console.WriteLine("The priority of Ipc Channel:{0}",ipcChannel.ChannelPriority); RemotingConfiguration.RegisterWellKnownServiceType(typeof(RemotingServer.RemotingObject), "RemotingObject",WellKnownObjectMode.Singleton); Console.ReadKey(); } } }
RemotingClinet
using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; using RemotingServer; namespace RemotingClient { class Program { static void Main(string[] args) { RemotingObject proxyTcp = Activator.GetObject(typeof (RemotingObject), "tcp://localhost:2046/RemotingObject") as RemotingObject; if (proxyTcp == null) { Console.WriteLine("连接Tcp服务失败!"); return; } RemotingObject proxyHttp = Activator.GetObject(typeof(RemotingObject), "http://localhost:9001/RemotingObject") as RemotingObject; if (proxyHttp==null) { Console.WriteLine("连接Http服务失败!"); return; } RemotingObject proxyIpc = Activator.GetObject(typeof(RemotingObject), "ipc://IpcTest/RemotingObject") as RemotingObject; if (proxyIpc == null) { Console.WriteLine("连接IPC失败!"); return; } // 输出信息 Console.WriteLine("This call object by TcpChannel, 100 + 200 = {0}", proxyTcp.TestTcpAdd(100, 200)); Console.WriteLine("This call object by HttpChannel, 100 - 200 = {0}", proxyHttp.TestHttpMinus(100, 200)); Console.WriteLine("This call object by IpcChannel, 100 * 200 = {0}", proxyIpc.TestMultiIpc(100, 200)); Console.WriteLine("Press any key to exit!"); Console.ReadLine(); } } }
备注:
Remoting在HttpChannel下抛“指定的 SOAPAction 无效
解决方法:
1:将Server和Client所在的程序集修改成相同的程序集名。
http://blog.csdn.net/lilin8905/article/details/6232640
2:在需要使用httpChannel的方法上面加上SoapMethod标签
[SoapMethod(XmlNamespace = "命名空间", SoapAction = "命名空间#方法名")]
http://blog.csdn.net/sloder/article/details/8694560