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C#中两个List<TModel>中根据指定条件--判断并获取不同数据的数据集合

原始需求:已经插入的数据不再重复插入(所有数据中排除已有数据,不存在数据以新对象形式存储在对象三种)

方式一:

 public class Test
    {
        public int age { get; set; }
        public string name { get; set; }
        public int score { get; set; }
    }
            List<Test> list1 = new List<Test>();
            list1.Add(new Test { score = 10, name = "001" });
            list1.Add(new Test { score = 20, name = "002" });
            list1.Add(new Test { score = 30, name = "003" });
            list1.Add(new Test { score = 40, name = "004" });
            list1.Add(new Test { score = 50, name = "005" });
            list1.Add(new Test { score = 60, name = "005" });

            List<Test> list2 = new List<Test>();
            list2.Add(new Test { score = 10, name = "001" });
            list2.Add(new Test { score = 20, name = "002" });
            list2.Add(new Test { score = 30, name = "003" });
            list2.Add(new Test { score = 40, name = "004" });

            //list3 return 2
            List<Test> list3 = list1.Where(x => !list2.Any(x2 => x.score == x2.score)).ToList();
            //list4 return 2
            List<Test> list4 = list1.Where(x => list2.All(x2 => x.score != x2.score)).ToList();

            MessageBox.Show("list3==" + list3.Count+"\r\nlist4==" + list4.Count);     

方式二:list1、list2数据参考方式一

public class DifferentModel : IEqualityComparer<Test>
    {
        public bool Equals(Test x, Test y)
        {
            return x.score == y.score;
        }

        public int GetHashCode(Test obj)
        {
            return obj.ToString().GetHashCode();
        }
    }

List<Test> different = list1.Except(list2, new DifferentModel()).ToList();//差集

MessageBox.Show("different=="+different.Count);

方式三:仅供参考,根据实际情况注意Contains关键字 注意使用——不建议使用

//return 2

List<Test> temp = list1.Where(p => !list2.Select(b => b.score).Contains(p.score)).ToList();
MessageBox.Show("temp=="+temp.Count);

 

posted on 2019-10-09 09:50  sunwugang  阅读(3087)  评论(0编辑  收藏  举报