链接:
http://poj.org/problem?id=1273
代码:
//Dinic #include<stdio.h> #include<string.h> #include<queue> #include<algorithm> using namespace std; const int MAXN = 1005; const int oo = 1e9+7; struct Edge { int v, flow, next; }edge[MAXN]; int Head[MAXN], cnt; int Layer[MAXN]; void InIt() { cnt = 0; memset(Head, -1, sizeof(Head)); } void AddEdge(int u, int v, int flow) { edge[cnt].v = v; edge[cnt].flow = flow; edge[cnt].next = Head[u]; Head[u] = cnt++; swap(u, v); edge[cnt].v = v; edge[cnt].flow = 0; edge[cnt].next = Head[u]; Head[u] = cnt++; } bool BFS(int start, int End) /// 分层 { memset(Layer, 0, sizeof(Layer)); queue<int> Q; Q.push(start); Layer[start] = 1; while(Q.size()) { int u = Q.front();Q.pop(); if(u == End)return true; for(int j=Head[u]; j!=-1; j=edge[j].next) { int v = edge[j].v; if(Layer[v] == 0 && edge[j].flow) /// 判断Layer[v]==0,可以减少循环 { Layer[v] = Layer[u] + 1; Q.push(v); } } } return false; } int DFS(int u, int MaxFlow, int End) /// DFS返回的是这条路上的最大流(最小值) { ///MaxFlow代表从源点起的最大流量 if(u == End)return MaxFlow; int uflow = 0; ///从u点到汇点的最大流量 for(int j=Head[u]; j!=-1; j=edge[j].next) { int v = edge[j].v; if(Layer[v]==Layer[u]+1 && edge[j].flow) { int flow = min(edge[j].flow, MaxFlow-uflow); flow = DFS(v, flow, End); edge[j].flow -= flow; edge[j^1].flow += flow; uflow += flow; if(uflow == MaxFlow) break; } } if(uflow == 0) Layer[u] = 0; return uflow; } int Dinic(int start, int End) { int MaxFlow = 0; while(BFS(start, End) == true) /// 先找出一条从Start到End的路 MaxFlow += DFS(start, oo, End); return MaxFlow; } int main() { int N, M; while(scanf("%d%d", &M, &N) != EOF) { int u, v, flow; InIt(); while(M--) { scanf("%d%d%d", &u, &v, &flow); AddEdge(u, v, flow); } printf("%d\n", Dinic(1, N)); } return 0; }
勿忘初心