形参引用类型_而传入的实参随便时
/*
如下,函数的形参是引用类型,如果把一个不设定为引用类型的参数传进去,效果入下。
基本如预料。
*/
#include <iostream>
using namespace std;
void func(int& i)
{
i = 1;
}
void main()
{
int x = 9;
cout<<"before:\t"<<x<<endl;
func(x);
cout<<"after:\t"<<x<<endl;
system("pause");
}
/*
output:
before:9
after:1
*/
#include <iostream>
using namespace std;
void func(int& i)
{
i = 1;
}
void main()
{
int y = 9;
int& x = y;
cout<<"before:\t"<<x<<","<<y<<endl;
func(x);
cout<<"after:\t"<<x<<","<<y<<endl;
system("pause");
}
/*
output:
before:9,9
after:1,1
*/
#include <iostream>
using namespace std;
void func(int& i)
{
i = 1;
}
void func1(int i)
{
i = 2;
}
void main()
{
int y = 9;
int& x = y;
cout<<"before:\t"<<x<<","<<y<<endl;
//func(x);
func1(x);
cout<<"after:\t"<<x<<","<<y<<endl;
system("pause");
}
/*
output:
before:9,9
after:9,9
*/
-------------------------------------------------
哎,理解不够,放几个例子对比吧。