crypto

一 异性相吸

a = '0110000101110011011000010110010001110011011000010111001101100100011000010111001101100100011000010111001101100100011000010111001101100100011000010111001101100100011000010111001101100100011000010111001101100100011000010111001101100100011000010111001101100100011100010111011101100101011100110111000101100110'
b = '0000011100011111000000000000001100001000000001000001001001010101000000110001000001010100010110000100101101011100010110000100101001010110010100110100010001010010000000110100010000000010010110000100011000000110010101000100011100000101010101100100011101010111010001000001001001011101010010100001010000011011'
c = ''

for i in range(len(a)):
if(a[i] == b[i]):
c+='0'
else:
c+='1'
print(c)

0110011001101100011000010110011101111011011001010110000100110001011000100110001100110000001110010011100000111000001110010011100100110010001100100011011100110110011000100011011101100110001110010011010101100010001101010011010001100001001101110011010000110011001101010110010100111000001110010110010101111101二转十六 十六转文

 二 RSA

明显pub.txt是一个公钥解析

 

 

 三 还原大师

# -*- coding: utf-8 -*-
#!/usr/bin/env python
import hashlib

#print hashlib.md5(s).hexdigest().upper()
k = 'TASC?O3RJMV?WDJKX?ZM' #要还原的明文
for i in range(26):
temp1 = k.replace('?',str(chr(65+i)),1)
for j in range(26):
temp2 = temp1.replace('?',chr(65+j),1)
for n in range(26):
temp3 = temp2.replace('?',chr(65+n),1)
s = hashlib.md5(temp3.encode('utf8')).hexdigest().upper()#注意大小写
if s[:4] == 'E903': #检查元素
print (s) #输出密文

运行得到flag{E9032994DABAC08080091151380478A2}

四 robomunicatio