单精度浮点数操作
用数组存储32位单精度浮点数，并且实现有效位右移，有效数加法等，可用于计算机浮点加减法的底层模拟。
1 package com.computerOrganizationAndArchitecture.floatQperation;
2
3 import com.computerOrganizationAndArchitecture.singleprecisionfloat.SinglePrecision;
4
5 /**
6 * Created by XuTao on 2018/12/8 20:24
7 * 这里用数组来存储32位的浮点数,
8 */
9 public class BinaryArray {
10 protected int [] binArr;
11 private int len;
12 public BinaryArray(){
13 len = 32;
14 binArr = new int[32];
15 }
16 public BinaryArray(String s){
17 len =32;
18 binArr = new int[32];
19 for (int i =0 ;i<32;i++){
20 binArr[i] = s.charAt(i)=='1'?1:0;
21 }
22 }
23 public BinaryArray(String s,int len){ //自定义长度
24 this.len =len;
25 binArr = new int[len];
26 for (int i =0 ;i<len;i++){
27 binArr[i] = s.charAt(i)=='1'?1:0;
28 }
29 }
30 public BinaryArray(double n){
31 len =32;
32 binArr = new int[32];
33 String ss= new SinglePrecision().Float2Binary(n);//https://www.cnblogs.com/XT-xutao/p/9906351.html
34 String s= ss.charAt(0)+ss.substring(2,10)+ss.substring(11);
35 for (int i =0 ;i<32;i++){
36 binArr[i] = s.charAt(i)=='1'?1:0;
37 }
38 }
39
40 public void shiftRight(int n){//右移n位
41 int [] temp = new int[n];
42 for (int i=23;i>=n;i--){//移动
43 binArr[i]=binArr[i-n];
44 }
45 for (int i=0;i<n;i++){//补0
46 binArr[i]=0;
47 }
48 }
49 public String toString(){
50 String s= "";
51 for (int i =0;i<len;i++){
52 s+=binArr[i];
53 }
54 return s;
55 }
56 public String toString(int []binArr){
57 String s= "";
58 for (int i =0;i<binArr.length;i++){
59 s+=binArr[i];
60 }
61 return s;
62 }
63 public String toExpString(){
64 String s= "";
65 for (int i =1;i<9;i++){
66 s+=binArr[i];
67 }
68 return s;
69 }
70 public String toSignificandString(){ // 24位的
71 String s= "";
72 for (int i =9;i<len;i++){
73 s+=binArr[i];
74 }
75 return "1"+s;
76 }
77 public int getExp (){
78 return Integer.valueOf(toExpString(),2);
79 }
80
81 public static int[] add(String a,String b){//N位二进制+1位进位（0/1）相加 =N+1位
82 //a,b长度要相等
83 int [] temp = new int[a.length()+1];
84 int [] arr1 = (new BinaryArray(a,a.length())).binArr;
85 int [] arr2 = (new BinaryArray(b,b.length())).binArr;
86 int carry = 0;
87 for (int i =a.length()-1;i>=0;i--){
88 temp[i+1] = arr1[i]+arr2[i]+carry;
89 carry=0;
90 if (temp[i+1]==2){
91 temp[i+1]=0;
92 carry = 1;
93 }
94 if (temp[i+1]==3){
95 temp[i+1]=1;
96 carry = 1;
97 }
98 }
99 //最高位进位
100 temp[0] = carry==1?1:0;
101 return temp;
102 }
103
104 public int[] getNegative(){
105 int [] temp = new int[32];
106 for (int i=0;i<32;i++){
107
108 }
109 return temp;
110 }
111
112 public static void main(String[] args) {
113 BinaryArray ba = new BinaryArray(-879.5);
114 System.out.println(ba.toString());
115 //11000100 01011011 11100000 00000000
116 System.out.println(ba.toSignificandString());
117
118 }
119
120 }
