摘要: 3527: [Zjoi2014]力先除去qiq_iqi​,令g(i)=1i2g(i)=\frac{1}{i^2}g(i)=i21​式子变成Ei=∑j=1i−1qi∗g(i−j)−∑j=i+1nqi∗g(j−i)E_i=\sum_{j=1}^{i-1} q_i... 阅读全文
posted @ 2019-03-17 16:20 XSamsara 阅读(115) 评论(0) 推荐(0) 编辑