摘要: 题目链接:http://wikioi.com/solution/list/1401/题解链接:http://user.qzone.qq.com/619943612/blog/1377265690代码:#include #include #include using namespace std;short int N,K,f[101][10001];int main(){ cin>>N>>K; f[1][1]=1; for (int i=2;i=1) f[i][k]=(f[i][k]+f[i-1][k-j])%10000; else break; ... 阅读全文