快速幂
摘要:
http://ch.vijos.org/Contest/%E8%BE%BD%E5%AE%81%E7%9C%81%E9%98%9F%E4%BA%92%E6%B5%8B%20Weak%201/Problem/Show/%E5%BF%AB%E9%80%9F%E5%B9%82#include<stdio.h>#include<string>#include<iostream>using namespace std;string s;int mod;long long multy(long long q, long long n){ long long cnt = n 阅读全文
posted @ 2013-05-19 19:16 雨钝风轻 阅读(204) 评论(0) 推荐(0) 编辑