Vowel Counting

Vowel Counting

Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other)
Total Submission(s) : 58   Accepted Submission(s) : 18
Problem Description
The "Vowel-Counting-Word"(VCW), complies with the following conditions. Each vowel in the word must be uppercase. Each consonant (the letters except the vowels) must be lowercase. For example, "ApplE" is the VCW of "aPPle", "jUhUA" is the VCW of "Juhua". Give you some words; your task is to get the "Vowel-Counting-Word" of each word.
 

 

Input
The first line of the input contains an integer T (T<=20) which means the number of test cases. For each case, there is a line contains the word (only contains uppercase and lowercase). The length of the word is not greater than 50.
 

 

Output
For each case, output its Vowel-Counting-Word.
 

 

Sample Input
4 XYz application qwcvb aeioOa
 

 

Sample Output
xyz ApplIcAtIOn qwcvb AEIOOA
 

 

Author
AppleMan
 

 

Source
HDU 2nd “Vegetable-Birds Cup” Programming Open Contest
 
 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 #include <string.h>
 4 
 5 int main()
 6 {
 7   int T,L,i;
 8   char a[50];
 9   scanf("%d",&T);
10   while(T--)
11   {
12       scanf("%s",a);
13       L=strlen(a);
14       for(i=0;i<L;i++)
15       {
16         if(a[i]=='a'||a[i]=='e'||a[i]=='i'||a[i]=='o'||a[i]=='u')
17         {
18             a[i]-=32;
19             continue;
20         }
21         else if(a[i]=='A'||a[i]=='E'||a[i]=='I'||a[i]=='O'||a[i]=='U')
22         {
23             continue;
24         }
25         else
26         {
27             if(a[i]>='A'&&a[i]<='Z')
28             {
29                 a[i]+=32;
30                 continue;
31             }
32         }
33       }
34       printf("%s\n",a);
35   }
36   return 0;
37 }
View Code

 

posted @ 2014-05-24 19:37  Wurq  阅读(314)  评论(0编辑  收藏  举报