1385. 两个数组间的距离值

题目链接	1385. 两个数组间的距离值
思路	二分查找
题解链接	官方题解
关键点	标准库的利用；二分循环不变式（开区间）：nums[left] < target && nums[right] >= target
时间复杂度	\(O((n+m)\log m)\)
空间复杂度	\(O(1)\)

代码实现：

class Solution:
    def findTheDistanceValue(self, arr1: List[int], arr2: List[int], d: int) -> int:
        arr2.sort()
        n = len(arr2)

        def lower_bound(val):
            left, right = -1, n
            while left+1 < right:
                mid = (left+right)//2
                if arr2[mid] < val:
                    left = mid
                else:
                    right = mid
            return right

        cnt = 0
        for x in arr1:
            p = lower_bound(x)
            if (p == n or abs(x - arr2[p]) > d) and (
                p == 0 or abs(x - arr2[p - 1]) > d
            ):
                cnt += 1

        return cnt

Python-官方库

class Solution:
    def findTheDistanceValue(self, arr1: List[int], arr2: List[int], d: int) -> int:
        arr2.sort()
        cnt = 0
        for x in arr1:
            p = bisect_left(arr2, x)
            if (p == len(arr2) or abs(x - arr2[p]) > d) and (
                p == 0 or abs(x - arr2[p - 1]) > d
            ):
                cnt += 1

        return cnt