GetManifestResourceStream得到的Stream是null的解决
GetManifestResourceStream得到的Stream是null的解决
Ans: 参考
http://blog.csdn.net/blue_sky_blue_heart/archive/2005/12/17/555139.aspx
System.Reflection.Assembly asm = System.Reflection.Assembly.GetExecutingAssembly();
// Note that the name for the embedded resource is case sensitive and must match the file name.
Bitmap bmp = new Bitmap(asm.GetManifestResourceStream(asm.GetName().Name + "." + "pic.png"));
e.Graphics.DrawImage(bmp, 5, 8, new Rectangle(0, 0, bmp.Width, bmp.Height), GraphicsUnit.Pixel);
// Note that the name for the embedded resource is case sensitive and must match the file name.
Bitmap bmp = new Bitmap(asm.GetManifestResourceStream(asm.GetName().Name + "." + "pic.png"));
e.Graphics.DrawImage(bmp, 5, 8, new Rectangle(0, 0, bmp.Width, bmp.Height), GraphicsUnit.Pixel);
其实最主要的是在将图片资源的属性设置为“嵌入的资源”：“属性-生成操作-嵌入的资源”
注意GetManifestResourceStream函数的参数：asm.GetName().Name获得的只是当前命名空间的名称，如果在“pic.png”图片在当前工程的Photo目录下，那么该参数就该写成asm.GetName().Name + "." + "Photo" + "." + " pic.png"
