shell设置时间递减脚本

经常要用shell来做时间的定时任务,尤其是用sqoop脚本拉取数据的时候,那么假如当你要导入数据是残缺的时候呢,我写了一个能自定义时间并逐条递减的程序

#!/bin/bash

 

. /etc/profile

. ~/.bash_profile

 

set -x

cd $(dirname $0)

 

 

#ttt=259

for wl in $( seq 1 300); do

        #statements

 

DATE1=$(date -d "${wl} day ago 20170725" +%Y-%m-%d)   #20170725的前一天 遍历减一天

DATE2=$(date -d "$(($wl-1)) day ago 20170725" +%Y-%m-%d) #20170725这一天 遍历当天

dt=${DATE1//-/}  #设置时间格式用于分区

done

如果想获得当前时间递减就把 ago 20170725去掉就可以了

运行命令: bash -test1.sh 

运行结果:

++ export PATH

+ set -x

++ dirname test1.sh

+ cd .

+ HADOOP_BIN=/workspace/carkey/hadoop/latest/bin/hadoop

+ HIVE_BIN=/workspace/carkey/apache-hive-2.1.1-bin/bin/hive

+ SQOOP_BIN=/workspace/carkey/sqoop-1.4.6.bin__hadoop-2.0.4-alpha/bin/sqoop

++ seq 1 100

+ for ijk in '$( seq 1 100)'

++ date -d '1 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-24

++ date -d '0 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-25

+ dt=20170724

+ for ijk in '$( seq 1 100)'

++ date -d '2 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-23

++ date -d '1 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-24

+ dt=20170723

+ for ijk in '$( seq 1 100)'

++ date -d '3 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-22

++ date -d '2 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-23

+ dt=20170722

+ for ijk in '$( seq 1 100)'

++ date -d '4 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-21

++ date -d '3 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-22

+ dt=20170721

+ for ijk in '$( seq 1 100)'

++ date -d '5 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-20

++ date -d '4 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-21

+ dt=20170720

+ for ijk in '$( seq 1 100)'

++ date -d '6 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-19

++ date -d '5 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-20

+ dt=20170719

+ for ijk in '$( seq 1 100)'

++ date -d '7 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-18

++ date -d '6 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-19

+ dt=20170718

+ for ijk in '$( seq 1 100)'

++ date -d '8 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-17

++ date -d '7 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-18

+ dt=20170717

+ for ijk in '$( seq 1 100)'

++ date -d '9 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-16

++ date -d '8 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-17

+ dt=20170716

+ for ijk in '$( seq 1 100)'

++ date -d '10 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-15

++ date -d '9 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-16

+ dt=20170715

+ for ijk in '$( seq 1 100)'

++ date -d '11 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-14

++ date -d '10 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-15

+ dt=20170714

+ for ijk in '$( seq 1 100)'

++ date -d '12 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-13

++ date -d '11 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-14

+ dt=20170713

+ for ijk in '$( seq 1 100)'

++ date -d '13 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-12

++ date -d '12 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-13

+ dt=20170712

+ for ijk in '$( seq 1 100)'

++ date -d '14 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-11

++ date -d '13 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-12

+ dt=20170711

+ for ijk in '$( seq 1 100)'

++ date -d '15 day ago 20170725' +%Y-%m-%d

+ DATE1=2017-07-10

++ date -d '14 day ago 20170725' +%Y-%m-%d

+ DATE2=2017-07-11

+ dt=20170710


  

posted @ 2017-11-03 13:39  willie-WangLiang  阅读(597)  评论(0编辑  收藏  举报