随笔 - 373  文章 - 1  评论 - 771  阅读 - 137万

数学图形(1.45)毛雷尔玫瑰(Maurer rose)

毛雷尔玫瑰,也有的翻译是毛瑞尔,它是一种很漂亮的图形.玫瑰线的变异品种.

我没有找到其中文的解释,有兴趣可以看下维基上的相关页面.

Maurer rose of the rose r = sin() consists of the 360 lines successively connecting the above 361 points. Thus a Maurer rose is a polygonal curve with vertices on a rose.

A Maurer rose can be described as a closed route in the polar plane. A walker starts a journey from the origin, (0, 0), and walks along a line to the point (sin(nd), d). Then, in the second leg of the journey, the walker walks along a line to the next point, (sin(n·2d), 2d), and so on. Finally, in the final leg of the journey, the walker walks along a line, from (sin(n·359d), 359d) to the ending point, (sin(n·360d), 360d). The whole route is the Maurer rose of the rose r = sin(). A Maurer rose is aclosed curve since the starting point, (0, 0) and the ending point, (sin(n·360d), 360d), coincide.

相关软件参见:数学图形可视化工具,使用自己定义语法的脚本代码生成数学图形.

复制代码
vertices = 361

t = from 0 to 360

n = 2
d = 39

k = t*d*0.0174533

x = sin(n*k)*cos(k)
y = sin(n*k)*sin(k)

r = 10
x = x*r
y = y*r
z = z*r
复制代码

 

复制代码
vertices = 361

t = from 0 to 360

n = 6
d = 71

k = t*d*0.0174533

x = sin(n*k)*cos(k)
y = sin(n*k)*sin(k)

r = 10
x = x*r
y = y*r
z = z*r
复制代码

使用随机参数的代码:

复制代码
vertices = 361

t = from 0 to 360

n = rand_int2(3, 12)
d = rand_int2(1, 100)

k = t*d*0.0174533

x = sin(n*k)*cos(k)
y = sin(n*k)*sin(k)

r = 10
x = x*r
y = y*r
z = z*r
复制代码

 

posted on   叶飞影  阅读(3633)  评论(1编辑  收藏  举报
编辑推荐:
· go语言实现终端里的倒计时
· 如何编写易于单元测试的代码
· 10年+ .NET Coder 心语,封装的思维:从隐藏、稳定开始理解其本质意义
· .NET Core 中如何实现缓存的预热?
· 从 HTTP 原因短语缺失研究 HTTP/2 和 HTTP/3 的设计差异
阅读排行:
· 周边上新:园子的第一款马克杯温暖上架
· Open-Sora 2.0 重磅开源!
· 分享 3 个 .NET 开源的文件压缩处理库,助力快速实现文件压缩解压功能!
· Ollama——大语言模型本地部署的极速利器
· DeepSeek如何颠覆传统软件测试?测试工程师会被淘汰吗?
< 2025年3月 >
23 24 25 26 27 28 1
2 3 4 5 6 7 8
9 10 11 12 13 14 15
16 17 18 19 20 21 22
23 24 25 26 27 28 29
30 31 1 2 3 4 5

点击右上角即可分享
微信分享提示