数学图形(1.20)N叶草

有N个叶子的草

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vertices = 1000
t = from 0 to (2*PI)
r = 10
n = rand_int2(3, 10)
p = 1 + cos(n*t) + sin(n*t)^2
x = p*cos(t)
y = p*sin(t)

N叶草面_1

vertices = D1:512 D2:100

u = from 0 to (PI*2) D1
v = from 0.0 to 1.0 D2

r = 10
n = rand_int2(3, 10)
p = 1 + v*cos(n*u) + sin(n*u)^2

x = p*cos(u)
y = p*sin(u)

N叶草面_2

vertices = D1:512 D2:100

u = from 0 to (PI*2) D1
v = from 0.0 to 4.0 D2

r = 10
n = rand_int2(3, 10)
p = 1 + cos(n*u) + sin(n*u)^2*v

x = p*cos(u)
y = p*sin(u)

 

 

posted on 2014-07-08 11:29  叶飞影  阅读(1051)  评论(0编辑  收藏  举报