实验7
实验三数据正确,且直观可读
#include<stdio.h> #include<string.h> #include<stdlib.h> #define N 10 typedef struct student{ int num; char name[20]; int score; }STU; int main(){ FILE *fin; int i=0,j=1; STU st[N]; fin=fopen("file4.dat","r"); if( !fin ) { printf("fail to open file4.dat\n"); exit(0); } while(!feof(fin)){ fscanf(fin,"%d %s %d",&st[i].num, st[i].name, &st[i].score); i++; } for(j=0;j<N;j++){ printf("%d %s %d",st[j].num, st[j].name, st[j].score); } fclose(fin); return 0; }
实验四 flie4.dat数据直观可读
#include <stdio.h> #include <string.h> #include <stdlib.h> const int N = 10; // 定义结构体类型struct student,并定义其别名为STU typedef struct student { long int id; char name[20]; float objective; /*客观题得分*/ float subjective; /*操作题得分*/ float sum; char level[10]; }STU; // 函数声明 void input(STU s[], int n); void output(STU s[], int n); void process(STU s[], int n); int main() { STU stu[N]; printf("录入%d个考生信息: 准考证号,姓名,客观题得分(<=40),操作题得分(<=60)\n", N); input(stu, N); printf("\n对考生信息进行处理: 计算总分,确定等级\n"); process(stu, N); printf("\n打印考生完整信息: 准考证号,姓名,客观题得分,操作题得分,总分,等级\n"); output(stu, N); return 0; } // 从文本文件examinee.txt读入考生信息:准考证号,姓名,客观题得分,操作题得分 void input(STU s[], int n) { FILE *fin; int i=0; fin=fopen("examinee.txt","r"); if( !fin ) { printf("fail to open examinee.txt\n"); exit(0); } while(!feof(fin)){ fscanf(fin,"%d %s %f %f",&s[i].id, s[i].name, &s[i].objective, &s[i].subjective); i++; } fclose(fin); } // 输出考生完整信息: 准考证号,姓名,客观题得分,操作题得分,总分,等级 // 不仅输出到屏幕上,还写到文本文件result.txt中 void output(STU s[], int n) { FILE *fp ; int i; fp=fopen("result.txt","w"); if( !fp ) { printf("fail to open examinee.txt\n"); exit(0); } for(i=0;i<N;i++){ printf("%22d %8s %8.2f %10.2f %10.2f %-8s\n",s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level); fprintf(fp,"%-d %-s %-f %-f %-f %-s\n",s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level); } fclose(fp); } // 对考生信息进行处理:计算总分,排序,确定等级 void process(STU s[], int n) { int i,j; STU t; for(i=0;i<n;i++){ s[i].sum=s[i].objective+s[i].subjective; } for(i=0;i<n-1;i++) { for(j=i+1;j<n;j++){ if(s[i].sum<s[j].sum) { t=s[j]; s[j]=s[i]; s[i]=t; } } } for(i=0;i<n;i++){ if(i<0.1*n) strcpy(s[i].level,"优秀"); else if(i>=0.1*n&&i<0.5*n) strcpy(s[i].level,"合格"); else strcpy(s[i].level,"不合格"); } }