NOIonline记

没有做什么准备,也没什么惊喜。

自我感觉:50+100+100=250

民间数据:50+0+100=150

第二题是什么鬼啊,为啥我爆零了??好像是看错题了吗???

 

 好吧确实理解错了,没有仔细看题面一轮冒泡排序的定义,当成每轮只换一个了TwT这毛病要改啊

T1 50pts

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<algorithm>
 4 #include<cstring>
 5 #include<queue>
 6 #define rep(i,a,n) for(register int i = a;i <= n;++i)
 7 using namespace std;
 8 typedef long long ll;
 9 
10 ll read(){
11     ll a = 0;char c = getchar(),l = c;
12     while(c < '0'||c > '9')l = c,c = getchar();
13     while('0' <= c&&c <= '9')a = a*10+c-'0',c = getchar();
14     if(l == '-')return -a;return a;
15 }
16 
17 //head
18 
19 const int Maxn = 1e5+10;
20 int t[Maxn],a[Maxn],b[Maxn],u[Maxn],v[Maxn];
21 int T,n,m;
22 
23 int main(){
24     
25     freopen("sequence.in","r",stdin);
26     freopen("sequence.out","w",stdout);
27     
28     T = read();
29     while(T--){
30         n = read(),m = read();
31         rep(i,1,n)a[i] = read();
32         rep(i,1,n)b[i] = read();
33         rep(i,1,m)t[i] = read(),u[i] = read(),v[i] = read();
34         if(n == 2&&m == 1){
35             if(t[1] == 1){
36                 if(u[1] == v[1]){
37                     if(u[1] == 1){
38                         if(a[2] == b[2]&&(((a[1]-b[1])&1) == 0))puts("YES");
39                         else puts("NO");
40                     }
41                     else{
42                         if(a[1] == b[1]&&(((a[2]-b[2])&1) == 0))puts("YES");
43                         else puts("NO");
44                     }
45                 }
46                 else if((a[1]-a[2]) == (b[1]-b[2]))puts("YES");
47                 else puts("NO");
48             }
49             else{
50                 if(u[1] == v[1]){
51                     if(a[1] == b[1]&&a[2] == b[2])puts("YES");
52                     else puts("NO");
53                 }
54                 else{
55                     if((a[1]+a[2]) == (b[1]+b[2]))puts("YES");
56                     else puts("NO");
57                 }
58             }
59         }
60         else{
61             
62         }
63     }
64 return 0;
65 }
T2 0pts
1
#include<iostream> 2 #include<cstdio> 3 #include<algorithm> 4 #include<cstring> 5 #include<queue> 6 #define rep(i,a,n) for(register int i = a;i <= n;++i) 7 using namespace std; 8 typedef long long ll; 9 10 ll read(){ 11 ll a = 0;char c = getchar(),l = c; 12 while(c < '0'||c > '9')l = c,c = getchar(); 13 while('0' <= c&&c <= '9')a = a*10+c-'0',c = getchar(); 14 if(l == '-')return -a;return a; 15 } 16 17 const int Maxn = 2e5+10; 18 19 ll a[Maxn],p[Maxn]; 20 ll n,ans,o,x,m; 21 22 void merge_sort(int l,int r){ 23 if(l >= r)return; 24 int mid = l+r>>1,p = l,q = mid+1,cnt = 0; 25 int b[r-l+1]; 26 merge_sort(l,mid),merge_sort(mid+1,r); 27 while(p <= mid||q <= r) 28 if(p > mid||(q <= r&&a[q] < a[p])){ 29 b[cnt++] = a[q++]; 30 ans += mid-p+1; 31 } 32 else b[cnt++] = a[p++]; 33 for(int i = 0;i < cnt;i++)a[l+i] = b[i]; 34 } 35 36 int main(){ 37 38 freopen("bubble.in","r",stdin); 39 freopen("bubble.out","w",stdout); 40 41 n = read(),m = read(); 42 rep(i,1,n)a[i] = p[i] = read(); 43 merge_sort(1,n); 44 rep(i,1,m){ 45 o = read(),x = read(); 46 if(o == 1){ 47 if(p[x] < p[x+1])ans++; 48 else ans--; 49 swap(p[x],p[x+1]); 50 } 51 else printf("%lld\n",max(0ll,ans-x)); 52 } 53 return 0; 54 }
T3 100pts
1
#include<iostream> 2 #include<cstdio> 3 #include<algorithm> 4 #include<cstring> 5 #include<queue> 6 #define rep(i,a,n) for(register int i = a;i <= n;++i) 7 using namespace std; 8 typedef long long ll; 9 10 ll read(){ 11 ll a = 0;char c = getchar(),l = c; 12 while(c < '0'||c > '9')l = c,c = getchar(); 13 while('0' <= c&&c <= '9')a = a*10+c-'0',c = getchar(); 14 if(l == '-')return -a;return a; 15 } 16 17 int gcd(int a,int b){ 18 if(a == 0)return b; 19 return gcd(b%a,a); 20 } 21 22 const int Maxn = 2e5+10; 23 ll n,m,ans1; 24 ll a[Maxn],b[Maxn],s[Maxn]; 25 26 int main(){ 27 28 freopen("ring.in","r",stdin); 29 freopen("ring.out","w",stdout); 30 31 n = read(),m = read(); 32 rep(i,1,n)a[i] = read(); 33 34 sort(a+1,a+n+1); 35 36 rep(i,1,n-2)b[i] = a[i]*a[i+2]; 37 b[n-1] = a[n-1]*a[1],b[n] = a[n]*a[2]; 38 rep(i,1,n)s[i] = s[i-1]+b[i]; 39 40 rep(i,1,m){ 41 int k = read(); 42 if(k){ 43 int x = gcd(n,k),y = n/x; 44 ll ans = 0; 45 rep(j,1,x)ans += 1ll*a[(j-1)*y+1]*a[(j-1)*y+2]+a[j*y-1]*a[j*y] 46 +s[j*y-2]-s[(j-1)*y]; 47 cout << ans << endl; 48 } 49 else { 50 if(!ans1)rep(i,1,n)ans1 += a[i]*a[i]; 51 cout << ans1 << endl; 52 } 53 } 54 return 0; 55 }

 

posted @ 2020-03-08 15:29  TIH_HIT  阅读(238)  评论(0编辑  收藏  举报