摘要: function getUrlParam(url, name) { var pattern = new RegExp("[?&]" + name + "\=([^&]+)", "g"); var matcher = pattern.exec(url); var items = null; if (m 阅读全文
posted @ 2017-08-16 17:43 WangJunZzz 阅读(443) 评论(0) 推荐(0) 编辑