python爆破定长密码脚本 

def get_pwd(str, num):#str为可选字符集，num为密码长度
        if(num == 1):
            for x in str:
                yield x
        else:
            for x in str:
                for y in get_pwd(str, num-1):
                    yield x+y

strKey=""#可选字符集
for i in range(33,127):#所有可见字符
    strKey+=chr(i)
    
for x in get_pwd(strKey,17):
    #x+="0823}"
    print(x)
posted @ 2017-02-04 15:24  M4x  阅读(824)  评论(0)  编辑  收藏  举报