acwing1240. 完全二叉树的权值
ACWING1240. 完全二叉树的权值
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <cmath>
typedef long long LL;
using namespace std;
const int maxn = 1e5 + 10;
LL n;
int a[maxn];
vector<pair<LL, int>> ans; // 结果,层数
int main()
{
cin >> n;
for (int i = 1; i <= n; i ++ )
{
scanf("%d", &a[i]);
}
int base = 1, level = 1;
while (base <= n)
{
// cout << level << endl;
LL temp = 0;
int end = pow(2, level) - 1;
if (end > n) end = n;
for (int i = base; i <= end; i ++ )
{
temp += a[i];
}
ans.push_back({temp, level});
level ++;
base = pow(2, level -1);
}
sort(ans.begin(), ans.end());
cout << ans.back().second <<endl;
return 0;
}
记录下来每一层的值的信息,然后排序
如果加的数量都是很大的话,需要用到long long
有什么问题可以加qq:1281372141进行交流