go 结构体列表比较是否相等

使用reflect的DeepEqual方法

场景1:结构体列表按顺序匹配(直接比较)

package main
import (
"fmt"
"reflect"
)
type Student struct {
Age int
Score int
}
func main() {
s1 := []Student{
{Age: 1, Score: 10},
{Age: 2, Score: 20},
{Age: 3, Score: 30},
}
s2 := []Student{
{Age: 1, Score: 10},
{Age: 2, Score: 20},
{Age: 3, Score: 30},
}
fmt.Println(reflect.DeepEqual(s1, s2))
s3 := []Student{
{Age: 1, Score: 10},
{Age: 2, Score: 20},
{Age: 3, Score: 30},
}
s4 := []Student{
{Age: 3, Score: 30},
{Age: 1, Score: 10},
{Age: 2, Score: 20},
}
fmt.Println(reflect.DeepEqual(s3, s4))
}

场景2:结构体列表不按顺序匹配(用map比较)

package main
import (
"fmt"
"reflect"
)
type Student struct {
Age int
Score int
}
func compare(a, b []Student) bool {
am := make(map[Student]bool, len(a))
bm := make(map[Student]bool, len(b))
return reflect.DeepEqual(am, bm)
}
func main() {
s1 := []Student{
{Age: 1, Score: 10},
{Age: 2, Score: 20},
{Age: 3, Score: 30},
}
s2 := []Student{
{Age: 1, Score: 10},
{Age: 2, Score: 20},
{Age: 3, Score: 30},
}
fmt.Println(compare(s1, s2))
s3 := []Student{
{Age: 1, Score: 10},
{Age: 2, Score: 20},
{Age: 3, Score: 30},
}
s4 := []Student{
{Age: 3, Score: 30},
{Age: 1, Score: 10},
{Age: 2, Score: 20},
}
fmt.Println(compare(s3, s4))
}

posted on   王景迁  阅读(9)  评论(0编辑  收藏  举报

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