实验6

task4

#include <stdio.h>
#include <string.h>
#define N 10
typedef struct {
    char isbn[20]; 
    char name[80]; 
    char author[80]; 
    double sales_price; 
    int sales_count; 
} Book;
void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);
int main() {
    Book x[N] = { {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59},
    {"978-7-5133-5261-1", "李白来到旧金山", "谭夏阳", 48, 16},
    {"978-7-5617-4347-8", "陌生人日记", "周怡芳", 72.6, 27},
    {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
    {"978-7-5046-9568-0", "数据化决策", "道格拉斯·W·哈伯德", 49,
    42},
    {"978-7-5133-4388-6", "美好时代的背后", "凯瑟琳.布", 34.5, 39},
    {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇",
    37.5, 55},
    {"978-7-5321-5691-7", "何为良好生活", "陈嘉映", 29.5 , 31},
    {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118,
    42},
    {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5,
    44} };
    printf("图书销量排名: \n");
    sort(x, N);
    output(x, N);
    printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
    return 0;
}

void output(Book x[], int n) {
    printf("ISBN号\t\t\t书名\t\t\t\t作者\t\t\t售价\t销售册数\n");
    for (int i = 0; i < n; i++) {
        printf("%-20s\t%-30s\t%-20s\t%g\t%d\n", x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count);
    }
}

void sort(Book x[], int n) {
    for (int i = 0; i < n; i++) {
        for (int j = i; j < n; j++) {
            if (x[i].sales_count <= x[j].sales_count) {
                int t = x[i].sales_count;
                x[i].sales_count = x[j].sales_count;
                x[j].sales_count = t;
                t = x[i].sales_price;
                x[i].sales_price = x[j].sales_price;
                x[j].sales_price = t;
                char tt[100];
                strcpy(tt, x[i].isbn);
                strcpy(x[i].isbn, x[j].isbn);
                strcpy(x[j].isbn, tt);
                strcpy(tt, x[i].name);
                strcpy(x[i].name, x[j].name);
                strcpy(x[j].name, tt);
                strcpy(tt, x[i].author);
                strcpy(x[i].author, x[j].author);
                strcpy(x[j].author, tt);
            }
        }
    }
}

double sales_amount(Book x[], int n) {
    double sum = 0.0;
    for (int i = 0; i < n; i++) {
        sum += x[i].sales_price * x[i].sales_count * 1.0;
    }
    return sum;
}

 

 

 

 

task5

#include <stdio.h>
typedef struct {
    int year;
    int month;
    int day;
} Date;

void input(Date* pd); 
int day_of_year(Date d); 

void test1() {
    Date d;
    int i;
    printf("输入日期:(以形如2023-12-11这样的形式输入)\n");
    for (i = 0; i < 3; ++i) {
        input(&d);
        printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day,
            day_of_year(d));
    }
}

void test2() {
    Date Alice_birth, Bob_birth;
    int i;
    int ans;
    printf("输入Alice和Bob出生日期:(以形如2023-12-11这样的形式输入)\n");
    for (i = 0; i < 3; ++i) {
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth, Bob_birth);
        if (ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if (ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}

int main() {
    printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
    test1();
    printf("\n测试2: 两个人年龄大小关系\n");
    test2();
}

void input(Date* pd) {
    scanf("%d-%d-%d", &(*pd).year, &(*pd).month, &(*pd).day);
}

int day_of_year(Date d) {
    int m[13] = { 0, 31,28,31,30,31,30,31,31,30,31,30,31 };
    if ((d.year % 4 == 0 && d.year % 400 == 0) || d.year % 4 == 0) {
        m[2] = 29;
    }
    int sum = 0;
    for (int i = 1; i <= d.month - 1; i++) {
        sum += m[i];
    }
    sum += d.day;
    return sum;
}

int compare_dates(Date d1, Date d2) {
    int ans;
    if (d1.year < d2.year) {
        ans = -1;
        return ans;
    }
    else if (d1.year > d2.year) {
        ans = 1;
        return ans;
    }
    else {
        if (d1.month < d2.month) {
            ans = -1;
            return ans;
        }
        else if (d1.month > d2.month) {
            ans = 1;
            return ans;
        }
        else {
            if (d1.day < d2.day) {
                ans = -1;
                return ans;
            }
            else if (d1.day > d2.day) {
                ans = 1;
                return ans;
            }
            else {
                ans = 0;
                return ans;
            }
        }
    }
}

 

 

 

task6

#include <stdio.h>
#include <string.h>
enum Role { admin, student, teacher };
typedef struct {
    char username[20]; 
    char password[20]; 
    enum Role type; 
} Account;

void output(Account x[], int n);
int main() {
    Account x[] = { {"A1001", "123456", student},
    {"A1002", "123abcdef", student},
    {"A1009", "xyz12121", student},
    {"X1009", "9213071x", admin},
    {"C11553", "129dfg32k", teacher},
    {"X3005", "921kfmg917", student} };
    int n;
    n = sizeof(x) / sizeof(Account);
    output(x, n);
    return 0;
}

void output(Account x[], int n) {
    for (int i = 0; i < n; i++) {
        printf("%s\t", x[i].username);
        int s = strlen(x[i].password);
        for (int i = 0; i < s; i++) {
            printf("*");
        }
        if (s < 7) {
            printf("\t\t");
        }
        else {
            printf("\t");
        }
        switch (x[i].type) {
        case admin:
            printf("admin");
            break;
        case student:
            printf("student");
            break;
        case teacher:
            printf("teacher");
        }
        printf("\n");
    }
}

 

 

 

task7

#include <stdio.h>
#include <string.h>
typedef struct {
    char name[20]; 
    char phone[12]; 
    int vip; 
} Contact;

void set_vip_contact(Contact x[], int n, char name[]); 
void output(Contact x[], int n); 
void display(Contact x[], int n); 

#define N 10
int main() {
    Contact list[N] = { {"刘一", "15510846604", 0},
    {"陈二", "18038747351", 0},
    {"张三", "18853253914", 0},
    {"李四", "13230584477", 0},
    {"王五", "15547571923", 0},
    {"赵六", "18856659351", 0},
    {"周七", "17705843215", 0},
    {"孙八", "15552933732", 0},
    {"吴九", "18077702405", 0},
    {"郑十", "18820725036", 0} };
    int vip_cnt, i;
    char name[20];
    printf("显示原始通讯录信息: \n");
    output(list, N);
    printf("\n输入要设置的紧急联系人个数: ");
    scanf("%d", &vip_cnt);
    printf("输入%d个紧急联系人姓名:\n", vip_cnt);
    for (i = 0; i < vip_cnt; ++i) {
        scanf("%s", name);
        set_vip_contact(list, N, name);
    }
    printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
    display(list, N);
    return 0;
}

void set_vip_contact(Contact x[], int n, char name[]) {
    for (int i = 0; i < n; i++) {
        if (strcmp(x[i].name, name) == 0) {
            x[i].vip = 1;
        }
    }
}

void display(Contact x[], int n) {

    for (int i = n - 1; i >= 0; i--) {
        for (int j = i; j >= 0; j--) {
            if (x[i].vip == 1 && x[j].vip == 0) {
                char nn[100];
                strcpy(nn, x[i].name);
                strcpy(x[i].name, x[j].name);
                strcpy(x[j].name, nn);
                strcpy(nn, x[i].phone);
                strcpy(x[i].phone, x[j].phone);
                strcpy(x[j].phone, nn);
                int ss = x[i].vip;
                x[i].vip = x[j].vip;
                x[j].vip = ss;
            }
        }
    }

    for (int i = 0; i < n; i++) {
        for (int j = i; j < n; j++) {
            if (strcmp(x[i].name, x[j].name) > 0 && x[i].vip != 1 && x[j].vip != 1) {
                char nn[100];
                strcpy(nn, x[j].name);
                strcpy(x[j].name, x[i].name);
                strcpy(x[i].name, nn);
                strcpy(nn, x[j].phone);
                strcpy(x[j].phone, x[i].phone);
                strcpy(x[i].phone, nn);
            }
        }
    }

    for (int i = 0; i < n; i++) {
        for (int j = i; j < n; j++) {
            if (x[i].vip == 1 && x[j].vip == 1) {
                if (strcmp(x[i].name, x[j].name) > 0){
                    char nn[100];
                    strcpy(nn, x[j].name);
                    strcpy(x[j].name, x[i].name);
                    strcpy(x[i].name, nn);
                    strcpy(nn, x[j].phone);
                    strcpy(x[j].phone, x[i].phone);
                    strcpy(x[i].phone, nn);
                }
            }
        }
    }

    output(x, n);
}
void output(Contact x[], int n) {
    int i;
    for (i = 0; i < n; ++i) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if (x[i].vip)
            printf("%5s", "*");
        printf("\n");
    }
}