C#实现复杂XML的序列化与反序列化

已知.xml(再此命名default.xml)文件，请将其反序列化到一个实例对象。

Default.XML文件如下:

<?xml version="1.0" encoding="utf-8"?>

<config> 
  <rules> 
    <rule name="namea"> 
      <params> 
        <item name="p" type="get" pattern="(ios|android|)"/>  
        <item name="cid" type="get" pattern="(ios|android|)"/>  
        <item name="type" type="get" pattern="(ios|android|)"/>  
        <item name="sort" type="get" pattern="(ios|android|)"/>  
        <item name="action" type="post" pattern="(ios|android|)"/>  
        <item name="userAgent" type="header" pattern="(ios|android|)"/> 
      </params> 
    </rule>  
    <rule name="nameb"> 
      <params> 
        <item name="p" type="get" pattern="(ios|android|)"/>  
        <item name="cid" type="get" pattern="(ios|android|)"/>  
        <item name="type" type="get" pattern="(ios|android|)"/>  
        <item name="sort" type="get" pattern="(ios|android|)"/>  
        <item name="action" type="post" pattern="(ios|android|)"/>  
        <item name="userAgent" type="header" pattern="(ios|android|)"/> 
      </params> 
    </rule>  
    <rule name="namec"> 
      <params> 
        <item name="p" type="get" pattern="(ios|android|)"/>  
        <item name="cid" type="get" pattern="(ios|android|)"/>  
        <item name="type" type="get" pattern="(ios|android|)"/>  
        <item name="sort" type="get" pattern="(ios|android|)"/>  
        <item name="action" type="post" pattern="(ios|android|)"/>  
        <item name="userAgent" type="header" pattern="(ios|android|)"/> 
      </params> 
    </rule>  
    <rule name="named"> 
      <params> 
        <item name="p" type="get" pattern="(ios|android|)"/>  
        <item name="cid" type="get" pattern="(ios|android|)"/>  
        <item name="type" type="get" pattern="(ios|android|)"/>  
        <item name="sort" type="get" pattern="(ios|android|)"/>  
        <item name="action" type="post" pattern="(ios|android|)"/>  
        <item name="userAgent" type="header" pattern="(ios|android|)"/> 
      </params> 
    </rule> 
  </rules> 
</config>

C#示例代码如下：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml.Serialization;
namespace 多层级反序列
{
    [XmlType(TypeName = "config")]
    public class XmlConfig
    {
        [XmlArray("rules")]
        public List<rule> rules { get; set; }
    }
    [XmlType(TypeName = "rule")]
    public class rule
    {
        [XmlAttribute]
        public string name { get; set; }
        [XmlArray("params")]
        public List<paramsItem> @params { get; set; }
    }
    [XmlType(TypeName = "item")]
    public class paramsItem
    {
        [XmlAttribute]
        public string name { get; set; }
        [XmlAttribute]
        public string type { get; set; }
        [XmlAttribute]
        public string pattern { get; set; }
    }
    class Program
    {
        static void Main(string[] args)
        {
            /*       XmlConfig xml1 = DeserializeFromXml<XmlConfig>("default.xml");   
             *           XmlConfig xml = new XmlConfig();       SerializeToXml<XmlConfig>("default.xml", xml);       */
            XmlConfig xml1 = DeserializeFromXml<XmlConfig>("default.xml");
        }
        /// <summary>     
        /// XML序列化某一类型到指定的文件   
        /// /// </summary>   
        /// /// <param name="filePath"></param>   
        /// /// <param name="obj"></param>  
        /// /// <param name="type"></param>   
        public static void SerializeToXml<T>(string filePath, T obj)
        {
            try
            {
                using (System.IO.StreamWriter writer = new System.IO.StreamWriter(filePath)) { System.Xml.Serialization.XmlSerializer xs = new System.Xml.Serialization.XmlSerializer(typeof(T)); xs.Serialize(writer, obj); }
            }
            catch (Exception ex) { }
        }
        /// <summary>     
        /// 从某一XML文件反序列化到某一类型   
        /// </summary>    
        /// <param name="filePath">待反序列化的XML文件名称</param>  
        /// <param name="type">反序列化出的</param>  
        /// <returns></returns>    
        public static T DeserializeFromXml<T>(string filePath)
        {
            try
            {
                if (!System.IO.File.Exists(filePath))
                    throw new ArgumentNullException(filePath + " not Exists");
                using (System.IO.StreamReader reader = new System.IO.StreamReader(filePath))
                {
                    System.Xml.Serialization.XmlSerializer xs = new System.Xml.Serialization.XmlSerializer(typeof(T));
                    T ret = (T)xs.Deserialize(reader);
                    return ret;
                }
            }
            catch (Exception ex)
            {
                return default(T);
            }
        }
    }
}