输入( 年 ,月 )打印日历()

def is_leapyear( year ):
    return True if year % 4 ==  0 and year % 100 !=  0 or year % 400 == 0 else False


def days_year( year ):
   return 366 if is_leapyear( year ) else 365


def days_month( year , month ):
    l = [ 31 , 29 , 31 , 30 , 31 , 30 , 31 , 31 , 30 , 31 , 30 , 31 ]
    u = [ 31 , 28 , 31 , 30 , 31 , 30 , 31 , 31 , 30 , 31 , 30 , 31 ]
    return l[ month-1 ]if is_leapyear( year ) else u[ month-1 ]


def get_week( year , month ):
    days = 0
    if ( 1990 <= year <= 2018 ) or ( 1 <= month <= 12 ) :
        for y in range( 1990 , year ):
            days += days_year( y )
        for m in range( 1 , month ):
            days += days_month( year , m )
        return ( days + 1 ) % 7
def get_week( year , month ): days = 0 if ( 1990 <= year <= 2018 ) or ( 1 <= month <= 12 ) : for y in range( 1990 , year ): days += days_year( y ) for m in range( 1 , month ): days += days_month( year , m ) return ( days + 1 ) % 7
while True: year , month = eval( input( ' Input year and month (year , month): ' ) ) days = 0 if ( 1990 <= year <= 2018 ) or ( 1 <= month <= 12 ): print( '\t{}年{}月'.format(year,month) ) print( '\t日\t一\t二\t三\t四\t五\t六' ) for week in range( get_week( year , month ) ): print( '\t'+' ',end='' ) for day in range( 1 , days_month( year , month ) + 1 ): print( '\t{: <2}'.format( day ) , end='' ) if ( day + get_week( year , month ) ) % 7 == 0 or day == days_month( year , month ) : print('') else : continue

 

posted @ 2018-12-06 11:21  TyroneYang  阅读(220)  评论(0编辑  收藏  举报