【基础算法】差分
一维差分
差分可以看成前缀和的逆运算
构造差分数组b[]
的方法:
作用:可以在\(O(1)\)的时间给区间[l, r]
内的数都加上一个数c
模板题:AcWing 797. 差分
#include <iostream>
using namespace std;
const int N = 1e5 + 10;
int n, m;
int a[N], b[N];
void insert(int l, int r, int c)
{
b[l] += c;
b[r + 1] -= c;
}
int main()
{
scanf("%d%d", &n, &m);
for(int i = 1; i <= n; i ++ )
{
scanf("%d", &a[i]);
insert(i, i, a[i]);
}
while(m -- )
{
int l, r, c;
scanf("%d%d%d", &l, &r, &c);
insert(l, r, c);
}
for(int i = 1; i <= n; i ++ )
{
a[i] = a[i - 1] + b[i];
printf("%d ", a[i]);
}
return 0;
}
二维差分
模板题:AcWing 798. 差分矩阵
#include <iostream>
using namespace std;
const int N = 1010;
int n, m, q;
int a[N][N], b[N][N];
void insert(int x1, int y1, int x2, int y2, int c)
{
b[x1][y1] += c;
b[x1][y2 + 1] -= c;
b[x2 + 1][y1] -= c;
b[x2 + 1][y2 + 1] += c;
}
int main()
{
scanf("%d%d%d", &n, &m, &q);
for(int i = 1; i <= n; i ++ )
for(int j = 1; j <= m; j ++ )
{
scanf("%d", &a[i][j]);
insert(i, j, i, j, a[i][j]);
}
while(q -- )
{
int x1, y1, x2, y2, c;
scanf("%d%d%d%d%d", &x1, &y1, &x2, &y2, &c);
insert(x1, y1, x2, y2, c);
}
for(int i = 1; i <= n; i ++ )
{
for(int j = 1; j <= m; j ++ )
{
a[i][j] = a[i - 1][j] + a[i][j - 1] - a[i - 1][j - 1] + b[i][j];
printf("%d ", a[i][j]);
}
puts("");
}
return 0;
}