104. 二叉树的最大深度
import java.util.LinkedList; import java.util.Queue; /** * 给定一个二叉树,找出其最大深度。 * <p> * 二叉树的深度为根节点到最远叶子节点的最长路径上的节点数。 * <p> * 说明: 叶子节点是指没有子节点的节点。 * <p> * 示例: * 给定二叉树 [3,9,20,null,null,15,7], * <p> * 3 * / \ * 9 20 * / \ * 15 7 * 返回它的最大深度 3 * <p> * 来源:力扣(LeetCode) * 链接:https://leetcode-cn.com/problems/maximum-depth-of-binary-tree * 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 */ public class MaxDepth { //递归 public static int maxDepth(TreeNode root) { if(null == root) return 0; int leftDepth = maxDepth(root.left); int rightDepth = maxDepth(root.right); return Math.max(leftDepth,rightDepth) + 1; } public static class TreeNode { int val; TreeNode left; TreeNode right; TreeNode(int x) { val = x; } public TreeNode(int val, TreeNode left, TreeNode right) { this.val = val; this.left = left; this.right = right; } } //广度优先算法 public static int MaxDepthV2(TreeNode root){ if(null == root){ return 0; } int maxDepth = 0; Queue<TreeNode> queue = new LinkedList<TreeNode>(); queue.offer(root); while (!queue.isEmpty()){ int size = queue.size(); while (size >0 ){ TreeNode node = queue.poll(); if(null != node.left){ queue.offer(node.left); } if(null != node.right){ queue.offer(node.right); } size--; } maxDepth++; } return maxDepth; } public static void main(String[] args) { TreeNode treeNode1 = new TreeNode(15); TreeNode treeNode2 = new TreeNode(7); TreeNode treeNode3 = new TreeNode(9,treeNode1,treeNode2); TreeNode treeNode4 = new TreeNode(20); TreeNode treeNode5 = new TreeNode(3,treeNode3,treeNode4); int maxDepth = MaxDepthV2(treeNode5); System.out.println("RESULT ====" + maxDepth); } }