python字符串操作、文件操作,英文词频统计预处理

 

1.字符串操作:

  • 解析身份证号:生日、性别、出生地等。
  • 凯撒密码编码与解码
  • 网址观察与批量生成

 解析身份证号:生日、性别、出生地等

def function3():
  print('请输入身份证号')
  ID = input()
  if len(ID) != 18:
    print('请输入有效的身份证号码')
  else:
    print('身份证号码格式正确')
  birth = ID[6:14]
  print('您的生日是:', format(birth))
  check = ID[14:17]
  if int(check) % 2 == 0:
      print('您的性别为:女')
  else:
      print('您的性别为:男')
  adress = ID[0:6]
  print('您的地址号码是:', format(adress), '可根据号码上网查')

结果截图:

 

凯撒密码编码与解码

def function1():
  str_raw = input("请输入明文:")
  k = int(input("请输入位移值:"))
  str_change = str_raw.lower()
  str_list = list(str_change)
  str_list_encry = str_list
  i = 0
  while i < len(str_list):
    if ord(str_list[i]) < 123-k:
      str_list_encry[i] = chr(ord(str_list[i]) + k)
    else:
      str_list_encry[i] = chr(ord(str_list[i]) + k - 26)
    i = i+1
  print ("加密结果为:"+"".join(str_list_encry))
def function2():
  str_raw = input("请输入密文:")
  k = int(input("请输入位移值:"))
  str_change = str_raw.lower()
  str_list = list(str_change)
  str_list_decry = str_list
  i = 0
  while i < len(str_list):
    if ord(str_list[i]) >= 97+k:
      str_list_decry[i] = chr(ord(str_list[i]) - k)
    else:
      str_list_decry[i] = chr(ord(str_list[i]) + 26 - k)
    i = i+1
  print ("解密结果为:"+"".join(str_list_decry))

结果截图:

 

网址观察与批量生成

def function4():
    for i in range(1, 10):
        url = 'http://www.baidu.com/{}.html'.format(i)
        print(url)

结果截图:

 

 

2.英文词频统计预处理

  • 下载一首英文的歌词或文章或小说。
  • 将所有大写转换为小写
  • 将所有其他做分隔符(,.?!)替换为空格
  • 分隔出一个一个的单词
  • 并统计单词出现的次数。

 

def function5():
    str1="""I'm a big big girl !
    In a big big world !
    It's not a big big thing if you leave me.
But I do do feel.
That I too too will miss you much.
Miss you much !
I can see the first leaf falling.
It's all yellow and nice.
It's so very cold outside.
Like the way I'm feeling inside.
I'm a big big girl !
In a big big world !
It's not a big big thing if you leave me.
But I do do feel.
That I too too will miss you much.
Miss you much !
Outside it's now raining.
And tears are falling from my eyes.
Why did it have to happen ?
Why did it all have to end ?
I'm a big big girl !
In a big big world !
It's not a big big thing if you leave me.
But I do do feel.
That I too too will miss you much.
Miss you much !
I have your arms around me ooooh like fire.
But when I open my eyes.
You're gone !
I'm a big big girl !
In a big big world !
It's not a big big thing if you leave me.
But I do do feel.
That I too too will miss you much.
Miss you much !
I'm a big big girl !
In a big big world !
It's not a big big thing if you leave me.
But I do feel that will miss you much !
Miss you so much !"""
    #字符
    s1 = str1.lower()
    print(s1)
    # 去掉空格
    str1 = str1.lstrip()
    print(str1)
    # 将歌词的每个单词分隔组成列表形式
    print("将歌词的每个单词分隔组成列表形式:")
    strList = str1.split()
    print(strList)
    # 计算单词出现的次数
    print("计算单词出现的次数:")
    strSet = set(strList)
    for word in strSet:
        print(word, strList.count(word))

 结果截图:

 

3.文件操作

  • 凯撒密码:从文件读入密函,进行加密或解密,保存到文件。
  • 词频统计:下载一首英文的歌词或文章或小说,保存为utf8文件。从文件读入文本进行处理。

凯撒密码

 

def function1():
    print("从文本读取到的密文是:")

    fo = open(r"..\bd\mypassword", "r",encoding="utf-8")
    str1 = fo.read()
    # 文本读取到的密码
    print(str1)
    fo.close()
    str_raw = str1

    k = int(input("请输入位移值:"))
    str_change = str_raw.lower()
    str_list = list(str_change)
    str_list_encry = str_list
    i = 0
    while i < len(str_list):
        if ord(str_list[i]) < 123 - k:
            str_list_encry[i] = chr(ord(str_list[i]) + k)
        else:
            str_list_encry[i] = chr(ord(str_list[i]) + k - 26)
        i = i + 1
    print("加密结果为:" + "".join(str_list_encry))
    print("写入文本中,请稍后。。。")
    fo = open(r"..\bd\mypassword", "w")
    fo.write(str_list_encry)
    fo.close()


def function2():
    str_raw = input("请输入密文:")
    k = int(input("请输入位移值:"))
    str_change = str_raw.lower()
    str_list = list(str_change)
    str_list_decry = str_list
    i = 0
    while i < len(str_list):
        if ord(str_list[i]) >= 97 + k:
            str_list_decry[i] = chr(ord(str_list[i]) - k)
        else:
            str_list_decry[i] = chr(ord(str_list[i]) + 26 - k)
        i = i + 1
    print("解密结果为:" + "".join(str_list_decry))
while True:
  print (u"1. 凯撒加密")
  print (u"2. 凯撒解密")
  choice = input("请选择:")
  if choice == "1":
   function1()
  elif choice == "2":
    function2()

  else:
    print (u"您的输入有误!")

 

词频统计

import os
path =os.getcwd()
fo=open(r"..\python1\what","r")
str1=fo.read()
#print(fo.readline())
fo.close()
s1=str1.lower()
#print(s1)
#去掉空格
str1=str1.lstrip()
#print(str1)
#将歌词的每个单词分隔组成列表形式
print("将歌词的每个单词分隔组成列表形式:")
strList=str1.split()
print(strList)
#计算单词出现的次数
print("计算单词出现的次数:")
strSet=set(strList)
for word in strSet:
   print(word,strList.count(word))

 

posted @ 2019-03-10 17:50  代码是肥钦喔  阅读(616)  评论(0编辑  收藏  举报