--獲取某年某月有多少周日(不包含周六) CREATE FUNCTION f_getnums ( @year_month VARCHAR(8) ) RETURNS INT AS BEGIN DECLARE @bdt DATETIME , @edt DATETIME , @i INT SET @i = 0 SET @bdt = CAST(@year_month + '-01' AS DATETIME) SET @edt = DATEADD(d, -1, DATEADD(month, 1, CAST(@year_month + '-01' AS DATETIME))) WHILE DATEDIFF(d, @bdt, @edt) >= 0 BEGIN IF --DATEPART(dw, @bdt) = 1 OR DATEPART(dw, @bdt) = 7 BEGIN SET @i = @i + 1 END SET @bdt = DATEADD(d, 1, @bdt) END RETURN @i END DECLARE @date DATETIME SET @date = '2012-12-01' --1.獲取某年某月有多少天 SELECT DATEDIFF(dd, @date, DATEADD(mm, 1, @date)) --2.获取某年某月有多少个星期日 select dbo.f_getnums(CONVERT(VARCHAR(07), @date, 120)) AS workday --3.获取某年某月有多少个工作日(仅不包含周日) select DATEDIFF(dd, @date, DATEADD(mm, 1, @date))- dbo.f_getnums(CONVERT(VARCHAR(07), @date, 120)) AS workday
欢迎转载,转载请注明出处:http://www.cnblogs.com/Tonyyang/