→阿童沐

財富==支撐一個人生存多長時間的能力!

导航

Oracle基本建表语句-

1 --创建用户
2 create user han identified by han default tablespace
3 users Temporary TABLESPACE Temp;
4 grant connect,resource,dba to han; //授予用户han开发人员的权利

 

 1 --------------------对表的操作--------------------------
2 --创建表
3 create table classes(
4 id number(9) not null primary key,
5 classname varchar2(40) not null
6 )
7 --查询表
8 select * from classes;
9
10 --删除表
11 drop table students;
12
13 --修改表的名称
14 rename alist_table_copy to alist_table;
15
16 --显示表结构
17 describe test --不对没查到

 

-----------------------对字段的操作-----------------------------------
--
增加列
alter table test add address varchar2(40);

--删除列
alter table test drop column address;

--修改列的名称
alter table test modify address addresses varchar(40;

--修改列的属性
alter table test modi

create table test1(
id number(9) primary key not null,
name varchar2(34)
)
rename test2 to test;

--创建自增的序列
create sequence class_seq increment by 1 start with 1 MAXVALUE 999999 NOCYCLE NOCACHE;

select class_seq.currval from dual

--插入数据
insert into classes values(class_seq.nextval,'软件一班')
commit;

--更新数据
update stu_account set username='aaa' where count_id=2;
commit;

--创建唯一索引
create unique index username on stu_account(username); --唯一索引 不能插入相同的数据

--行锁 在新打开的对话中不能对此行进行操作
select * from stu_account t where t.count_id=2 for update; --行锁

 

  1 --alter table stuinfo modify sty_id to stu_id;
2
3 alter table students drop constraint class_fk;
4 alter table students add constraint class_fk foreign key (class_id) references classes(id);--外键约束
5 alter table stuinfo add constraint stu_fk foreign key (stu_id) references students(id) ON DELETE CASCADE;--外键约束,级联删除
6
7 alter table stuinfo drop constant stu_fk;
8
9 insert into students values(stu_seq.nextval,'张三',1,sysdate);
10
11 insert into stuinfo values(stu_seq.currval,'威海');
12
13 select * from stuinfo;
14
15 create table zhuce(
16 zc_id number(9) not null primary key,
17 stu_id number(9) not null,
18 zhucetime date default sysdate
19
20 )
21
22 create table feiyong (
23 fy_id number(9) not null primary key,
24 stu_id number(9) not null,
25 mx_id number(9) not null,
26 yijiao number(7,2) not null default 0,
27 qianfei number(7,2) not null
28
29 )
30
31
32 create talbe fymingxi(
33 mx_id number(9) not null primary key,
34 feiyong number(7,2) not null, //共7位数字,小数后有两位
35 class_id number(9) not null
36 }
37
38 create table card(
39 card_id number(9) primary key,
40 stu_id number(9) not null,
41 money number(7,2) not null default 0,
42 status number(1) not null default 0 --0表可用,1表挂失
43 )
44
45 --链表查询
46
47 select c.classname||'_'||s.stu_name as 班级_姓名,si.address from classes c,students s , stuinfo si where c.id=s.class_id and s.id=si.stu_id;
48 insert into students values(stu_seq.nextval,'李四',1,sysdate);
49 insert into stuinfo values(stu_seq.currval,'南京');
50
51 --函数
52 select rownum,id,stu_name from students t order by id asc;
53
54
55 --中间表实现多对多关联
56 --(1 1, 1 n,n 1,n n )
57
58
59 --1 n的描述 1的表不作处理 n的表有1表的字段
60 --1 1的描述 主外键关联
61 --n n的描述 中间表实现多对多关联
62
63 create table course(
64 course_id number(9) not null,
65 couser_name varchar2(40) not null
66 )
67 alter table course to couse;
68 create table stu_couse(
69 stu_couse_id number(9) primary key,
70 stu_id number(9) not null,
71 couse_id number(9) not null
72
73 )
74
75 create unique index stu_couse_unq on stu_couse(stu_id,couse_id); --唯一学生
76 create sequence stu_couse_seq increment by 1 start with 1 MAXVALUE 999999 NOCYCLE NOCACHE;
77
78
79 create sequence couses_seq increment by 1 start with 1 MAXVALUE 999999 NOCYCLE NOCACHE;
80 insert into course values(couses_seq.nextval,'计算机原理');
81 insert into course values(couses_seq.nextval,'编译原理');
82 insert into course values(couses_seq.nextval,'数据库原理');
83 insert into course values(couses_seq.nextval,'数据结构');
84 insert into course values(couses_seq.nextval,'计算机基础');
85 insert into course values(couses_seq.nextval,'C语言初步');
86 commit;
87
88 insert into stu_couse values(stu_couse_seq.nextval,1,1);
89 insert into stu_couse values(stu_couse_seq.nextval,1,3);
90 insert into stu_couse values(stu_couse_seq.nextval,1,5);
91 insert into stu_couse values(stu_couse_seq.nextval,1,5);
92
93 insert into stu_couse values(stu_couse_seq.nextval,2,1);
94 commit;
95 select * from stu_couse;
96 select * from course;
97
98 --select s.stu_name,sc.couse_id, c.couser_name from students s,course c,stu_couse sc where stu_id=1
99
100 --select couse_id from stu_couse where stu_id=1
101
102 select cl.classname,s.stu_name,c.couser_name from stu_couse sc, students s,course c,classes cl where s.id=sc.stu_id and sc.couse_id=c.course_id and s.class_id=cl.id and s.id=1;
103
104 --班级——姓名
105 select c.classname,s.stu_name from students s,classes c where s.class_id=c.id and s.id=2;
106
107 select * from students s where s.id=2
108 --班级——姓名——课程
109
110 select cl.classname,s.stu_name,c.couse_name from stu_couse sc,students s,classes cl,couse c where sc.stu_id=s.id and sc.couse_id=c.couse_id and s.id=26;
111
112
113 --sql 语句的写法,现写出关联到的表,然后写出要查找的字段,第三 写出关联条件 ,记住在写关联到的表时先写数据多的表,这样有助于提高sql的效率
114
115 select c.couser_name,s.stu_name from stu_couse sc,students s,course c where c.course_id=1 and c.course_id=sc.couse_id and sc.stu_id=s.id;
116
117 select s.stu_name from students s,stu_couse sc where s.id=sc.stu_id group by s.id,s.stu_name;
118
119
120 select c.classname,count(sc.couse_id) from stu_couse sc,students s,classes c where s.class_id=c.id and s.id=sc.stu_id group by c.classname;
121
122 select s.stu_name, count(sc.couse_id) from stu_couse sc,students s,classes cl where s.id=sc.stu_id group by s.id,s.stu_name having count(sc.stu_couse_id)>3;
123 班级 学生 选课数量
124 select cl.classname,count(sc.stu_couse_id) from stu_couse sc,students s,classes cl where s.id=sc.stu_id and s.class_id=cl.id group by cl.classname;
125
126
127 --班级 学生 选课数量
128 select cl.classname,s.stu_name,count(sc.stu_couse_id) from stu_couse sc,students s,classes cl where s.id=sc.stu_id and s.class_id=cl.id group by s.stu_name;
129 select cl.classname,s.stu_name,count(sc.stu_couse_id) from stu_couse sc ,students s,classes cl where sc.stu_id=s.id and s.class_id=cl.id group by s.id;
130
131 select cl.classname,s.stu_name,count(sc.stu_couse_id) from stu_couse sc,students s,classes cl where sc.stu_id=s.id and s.class_id=cl.id group by s.stu_name;
132 --班级 学生 所选课程id 所选课程名称
133
134
135 --创建试图 目的把表联合起来 然后看成一个表,在与其他的联合进行查询
136 create view xsxk as select cl.classname, s.stu_name,c.couse_id, c.couse_name from stu_couse sc,students s,classes cl,couse c where sc.stu_id=s.id and sc.couse_id=c.couse_id and s.class_id=cl.id;
137
138 select * from xsxk
139
140
141 create view classstu as select s.id,c.classname,s.stu_name from students s,classes c where c.id=s.class_id;
142 drop view classstu; --删除视图
143 select * from classstu;
144
145 create view stu_couse_view as select s.id ,c.couse_name from stu_couse sc,students s,couse c where s.id=sc.stu_id and sc.couse_id=c.couse_id;
146 select * from stu_couse_view;
147
148 create view csc as select cs.classname,cs.stu_name,scv.couse_name from classstu cs,stu_couse_view scv where cs.id=scv.id;
149 select * from csc;
150
151
152 select * from classes cross join students; --全连接,相当于select * from classes,students;
153
154 select * from classes cl left join students s on cl.id=s.class_id; --左连接 不管左表有没有 都显示出来
155 select * from classes cl right join students s on cl.id=s.class_id; --右连接
156 select * from classes cl full join students s on cl.id=s.class_id; --全连接
157
158
159 insert into classes values(class_seq.nextval,'软件四班');
160
161 create table sales(
162 nian varchar2(4),
163 yeji number(5)
164
165 );
166 insert into sales values('2001',200);
167 insert into sales values('2002',300);
168 insert into sales values('2003',400);
169 insert into sales values('2004',500);
170 commit;
171 select * from sales;
172 drop table sale;
173
174
175 select s1.nian,sum(s2.yeji) from sales s1,sales s2 where s1.nian>=s2.nian group by s1.nian order by s1.nian desc;
176
177 select s1.nian,sum(s2.yeji) from sales s1,sales s2 where s1.nian>=s2.nian group by s1.nian;
178
179 s
180 年 年业绩总和
181 2001 200
182 2002 500
183 2003 900
184 2004 1400
185
186
187 create table test1(
188 t_id number(4)
189 );
190
191 create table org(
192 org_id number(9) not null primary key,
193 org_name varchar2(40) not null,
194 parent_id number(9)
195 );
196
197 create sequence org_seq increment by 1 start with 1 MAXVALUE 999999 NOCYCLE NOCACHE;
198 drop sequence org_seq;
199 insert into org values(1,'华建集团',0);
200 insert into org values(2,'华建集团一分公司',1);
201 insert into org values(3,'华建集团二分公司',1);
202 insert into org values(4,'华建集团财务部',1);
203 insert into org values(5,'华建集团工程部',1);
204 insert into org values(6,'华建集团一分公司财务处',2);
205 insert into org values(7,'华建集团一分公司工程处',2);
206
207 select * from org;
208 --不正确 不能实现循环
209 select b.org_id , b.org_name ,b.parent_id from org a,org b where a.org_id=7 and a.parent_id=b.org_id;
210 select * from org connect by prior parent_id=org_id start with org_id=7 order by org_id;
211 select * from org connect by prior org_id=parent_id start with org_id=1 order by org_id;
212
213 create table chengji(
214 cj_id number(9) not null primary key,
215 stu_cou_id number(9) not null,
216 fen number(4,1)
217
218 );
219 insert into chengji values(1,1,62);
220 insert into chengji values(2,2,90);
221 insert into chengji values(3,3,85);
222 insert into chengji values(4,4,45);
223 insert into chengji values(5,5,68);
224 insert into chengji values(6,6,87);
225 commit;
226 select * from chengji;
227 select * from stu_couse;
228 --在oracle 中好像不适用 alter table chengji change stu_cou_id stu_couse_id;alter table shop_jb change price1 price double;
229
230 学生姓名 平均分
231 select s.stu_name,avg(cj.fen) from stu_couse sc,chengji cj,students s where s.id=sc.stu_id and sc.stu_couse_id=cj.stu_couse_id group by s.id,s.stu_name;
232 select s.stu_name from students s,stu_couse sc,chengji cj where s.id=sc.stu_id and sc.stu_couse_id=cj.stu_couse_id group by s.id,s.stu_name;
233 select s.stu_name,cj.fen from students s,stu_couse sc,chengji cj where s.id=sc.stu_id and sc.stu_couse_id=cj.stu_couse_id and cj.fen>60;
234
235 学生姓名 科目 成绩
236 select s.stu_name,c.couse_name,cj.fen from stu_couse sc,students s,couse c,chengji cj where sc.stu_id=s.id and sc.couse_id=c.couse_id and sc.stu_couse_id=cj.stu_couse_id and cj.fen>60 order by=;
237
238 select * from stu_couse;
239
240 --集合运算
241 --选择了课程3的学生 union 选择了课程5的学生 并集
242 --选择了课程3 或者 选择了课程5的学生
243 select s.stu_name from students s,couse c,stu_couse sc where s.id=sc.stu_id and sc.couse_id=c.couse_id and c.couse_id=3
244 union
245 select s.stu_name from students s,couse c,stu_couse sc where s.id=sc.stu_id and sc.couse_id=c.couse_id and c.couse_id=5
246
247 --选择了课程3,5,2 的学生 intersect 选择课程1,2,4的学生 交集
248 --求选择了课程 2 并且 选择了课程 3 的学生 交集
249 select s.stu_name from students s,couse c,stu_couse sc where s.id=sc.stu_id and sc.couse_id=c.couse_id and c.couse_id=2
250 intersect
251 select s.stu_name from students s,couse c,stu_couse sc where s.id=sc.stu_id and sc.couse_id=c.couse_id and c.couse_id=3;
252
253
254 --选择了课程3,5,8的学生 minus 选择了课程1,7,8的学生 --差集
255 -- 求所有课程的成绩都大于 60 的学生 差集
256 select distinct(s.stu_name) from stu_couse sc,students s,couse c,chengji cj where sc.stu_id=s.id and sc.couse_id=c.couse_id and sc.stu_couse_id=cj.stu_couse_id and cj.fen>60
257 minus
258 select distinct(s.stu_name) from stu_couse sc,students s,couse c,chengji cj where sc.stu_id=s.id and sc.couse_id=c.couse_id and sc.stu_couse_id=cj.stu_couse_id and cj.fen<60




posted on 2011-12-28 12:57  阿童沐  阅读(882)  评论(0编辑  收藏  举报