360笔试编程题

360笔试题目：

C++简单实现：

 1 #include <stdio.h>
 2 #include <iostream>
 3 #include <math.h>
 4 #include <sstream>
 5 #include <cstring>
 6 #include <vector>
 7 #include <algorithm>
 8 
 9 using namespace std;
10 
11 
12 const int MAXWATCHTIMES = 2001;
13 const int MAXKINDS = 101;
14 int watchFlowers[MAXWATCHTIMES] = {0};
15 int flowerKinds[MAXKINDS] = {0};
16 
17 void getCount(int start, int anEnd, int & resultSingle);
18 
19 int main() {
20     int n;
21     int m;
22     vector<int> result;
23     cin >> n >> m;
24     result.clear();
25     for (int j = 0; j < n; ++j) {
26         cin >> watchFlowers[j];
27     }
28 
29     int Q;
30     int start;
31     int end;
32     int resultSingle = 0;
33     cin >> Q;
34     for (int i = 0; i <  Q; ++i) {
35         cin >> start >> end;
36         getCount(start,end,resultSingle);
37         result.push_back(resultSingle);
38     }
39 
40     vector<int>::iterator it = result.begin();
41     for (;it != result.end(); ++it) {
42         cout << *it << endl;
43     }
44 }
45 
46 void getCount(int start, int anEnd, int & resultSingle) {
47     start--;
48     anEnd--;
49     for (int k = 0; k < 101; ++k) {
50         flowerKinds[k] = 0;
51     }
52     for (int i = start; i <= anEnd; ++i) {
53         flowerKinds[watchFlowers[i]] = 1;
54     }
55 
56     resultSingle = 0;
57     for (int j = 0; j < 101; ++j) {
58         resultSingle += flowerKinds[j];
59     }
60 }

------------------------------------------------通过60%

 

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另附加第三道编程题，未做，留作参考！

posted @ 2018-08-28 08:31  一介草民李八千  阅读(233)  评论(0)  编辑  收藏  举报