Problem A: 好多书啊！

Description

每次开学，都要买好多教材，好多好多的money就这样不见了，见了，了，......

我们以教材款的总额来表示我们的伤心度。所以！我们需要首先计算出我们花了多少钱！

定义一个类Book，拥有

1.数据成员name（string类型）和price（double类型）。

2.构造函数（含缺省构造函数）以及析构函数。它们都要输出一行文字，格式见样例（注意输出最后有换行哦）。

3. getName、getPrice、setName、setPrice四个方法，如何定义参照给出的main函数的调用方法。

Input

输入有3行，每行包括1个字符串（不含空白符）及一个实数，中间用1个空格隔开。

Output

呃~看样例吧。好复杂的！

Sample Input

C 10

Data 20

Char 30

Sample Output

A book C++ is created.

A default book is created.

A default book is created.

A default book is created.

The four books are: C++ C Data Char

Their total price is 102

A book Char is erased.

A book Data is erased.

A book C is erased.

A book C++ is erased.

HINT

Append Code

#include<iostream>

#include<string.h>

using namespace std;

class Book

{

private:

    string name;

    double price;

public:

    Book(){cout<<"A default book is created.\n";}

    Book(string n,double p){name=n,price=p;cout<<"A book "<<name<<" is created.\n";}

    ~Book(){cout<<"A book "<<name<<" is erased.\n";}

    void setName(string n){name=n;}

    void setPrice(double p){price=p;}

    string getName(){return name;}

    double getPrice(){return price;}

 

};

int main()

{

    Book books[4]={Book("C++", 42.0)};

    string tmp;

    double sum, price;

    int i;

    for (i = 0; i < 3; i++)

    {

        cin>>tmp>>price;

        books[i + 1].setName(tmp);

        books[i + 1].setPrice(price);

    }

    sum = 0;

    for (i = 0; i < 4; i++)

    {

        sum += books[i].getPrice();

    }

    cout<<"The four books are: " << books[0].getName();

    for (i = 1; i < 4; i++)

    {

        cout<<" "<<books[i].getName();

    }

    cout<<endl<<"Their total price is "<<sum<<endl;

    return 0;

}