迷宫最短路

#include<iostream>
#include<queue>
#include<cstring>
#include<cstdio>
#define MAX 100
using namespace std;
const int INF = 10;
typedef pair<int, int >P;
int  d[MAX][MAX];
char imap[MAX][MAX];
int n, m;
int sx, sy;
int gx, gy;
int To[4][2] = { { 1, 0 }, { -1, 0 }, { 0, 1 }, { 0, -1 } };
int bfs()
{
	for (int i = 0; i < n; i++)
		for (int j = 0; j < m; j++)
			d[i][j] = INF;
	queue<P>que;
	que.push(P(sx, sy));
	d[sx][sy] = 0;
	while (que.size())
	{
		P t = que.front(); que.pop();
		if (t.first == gx&&t.second == gy)break;
		for (int i = 0; i < 4; i++)
		{
			int nx = To[i][0] + t.first;
			int ny = To[i][1] + t.second;
			if (nx >= 0 && nx < n&&ny >= 0 && ny < m&&imap[nx][ny] != '#'&&d[nx][ny] ==INF)
			{
				que.push(P(nx, ny));
				d[nx][ny] = d[t.first][t.second] + 1;
			}
		}
	}
	return d[gx][gy];
}
struct node
{
	int x;
	int y;
	int r;
	node(int X, int Y, int R) :x(X), y(Y), r(R){};
	node() :x(0), y(0), r(0){};
};
int BFS()
{
	memset(d, 0, sizeof(d));
	queue<node>que;
	que.push(node(sx, sy, 0));
	while (que.size())
	{
		node t = que.front(); que.pop();
		d[t.x][t.y] = 1;
		if (t.x == gx&&t.y == gy)
			return t.r;
		for (int i = 0; i < 4; i++)
		{
			int nx = To[i][0] + t.x;
			int ny = To[i][1] + t.y;
			if (nx >= 0 && nx < n&&ny >= 0 && ny < m&&imap[nx][ny] != '#'&&!d[nx][ny])
				que.push(node(nx, ny, t.r + 1));
		}
	}
	return INF;
}
int main()
{
	while (cin >> n >> m)
	{	
		int i, j;
		for (i = 0; i < n; i++)
			for (j = 0; j < m; j++)
			{
				cin >> imap[i][j];
				if (imap[i][j] == 'S')
				{
					sx = i;
					sy = j;
				}
				else if (imap[i][j] == 'G')
				{
					gx = i;
					gy = j;
				}
			}
		cout << "bfs:\t" << bfs() << endl;
		cout << "BFS:\t" << BFS() << endl;
	}
	return 0;
}

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posted @ 2015-04-18 13:56  Thereisnospon  阅读(127)  评论(0编辑  收藏  举报