uva 10625 Board Wrapping
https://vjudge.net/problem/UVA-10652
给出n个长方形,用一个面积尽量小的凸多边形把他们围起来
求木板占包装面积的百分比
输入给出长方形的中心坐标,长,宽,以及长方形顺时针旋转的角度
求凸包
处理输入:
长方形四个顶点的向量坐标=中心点的向量坐标+从中心出发的向量旋转长方形的旋转角度
#include<cstdio> #include<cmath> #include<algorithm> using namespace std; const double pi=acos(-1); const double eps=1e-10; int dcmp(double x,double y) { if(fabs(x-y)<eps) return 0; return x<y ? -1 : 1; } struct Point { double x,y; Point(double x=0,double y=0):x(x),y(y) { } }; typedef Point Vector; Point P[2401],ch[2401]; Vector operator + (Vector A,Vector B) { return Vector(A.x+B.x,A.y+B.y); } Vector operator - (Vector A,Vector B) { return Vector(A.x-B.x,A.y-B.y); } double torad(double j) { return j*pi/180; } double Cross(Vector A,Vector B) { return A.x*B.y-A.y*B.x; } Vector Rotate(Vector A,double rad) { return Vector(A.x*cos(rad)-A.y*sin(rad),A.x*sin(rad)+A.y*cos(rad)); } bool cmp(Point A,Point B) { if(!dcmp(A.x,B.x)) return A.y<B.y; return A.x<B.x; } int ConvexHull(Point *p,int n,Point *c) { sort(p,p+n,cmp); int m=0; for(int i=0;i<n;++i) { while(m>1 && Cross(c[m-1]-c[m-2],P[i]-c[m-2])<=0) m--; c[m++]=P[i]; } int k=m; for(int i=n-2;i>=0;--i) { while(m>k && Cross(c[m-1]-c[m-2],P[i]-c[m-2])<=0) m--; c[m++]=P[i]; } if(n>1) m--; return m; } double PolygonArea(Point *p,int n) { double area=0; for(int i=1;i<n-1;++i) area+=Cross(p[i]-p[0],p[i+1]-p[0]); return area/2; } int main() { int T,n,m,pc; double x,y,w,h,j,ang; double area1,area2; scanf("%d",&T); while(T--) { scanf("%d",&n); pc=0; area1=0; for(int i=1;i<=n;++i) { scanf("%lf%lf%lf%lf%lf",&x,&y,&w,&h,&j); Point o(x,y); ang=-torad(j); P[pc++]=o+Rotate(Vector(-w/2,-h/2),ang); P[pc++]=o+Rotate(Vector(-w/2,h/2),ang); P[pc++]=o+Rotate(Vector(w/2,-h/2),ang); P[pc++]=o+Rotate(Vector(w/2,h/2),ang); area1+=w*h; } m=ConvexHull(P,pc,ch); area2=PolygonArea(ch,m); printf("%.1lf %%\n",area1*100/area2); } }