[解题报告]HDU 1012 u Calculate e

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 21753    Accepted Submission(s): 9604


Problem Description
A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
 

 

Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
 

 

Sample Output
n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333
 

 

Source
 

 

Recommend
JGShining
 

 

 

 

不要企图去算n=0;

#include<stdio.h>
int main()
{
    double i,j,x,s=1;
    printf("n e\n- -----------\n0 1\n");
    for(i=1;i<10;i++)
    {
        printf("%lg ",i);
        x=1;
        for(j=1;j<=i;j++)
        x*=1/j;
        s+=x;
        if(i==8)
        {
            printf("%.9lf\n",s);
            continue;
        }
        printf("%.10lg\n",s);
    }
    return 0;
}

 

posted @ 2013-03-13 21:46  三人木君  阅读(165)  评论(0编辑  收藏  举报