用Python 根据文件名查找数据文件

#-*- coding: UTF-8 -*-

import os
import shutil
AllFiles=[]
NameFiles=[]
def findFie(filePath):
    pathDir = os.listdir(filePath)
    for allDir in pathDir:
       # print(allDir)
       AllFiles.append(allDir)
        #pass

#filepath = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\71\\71sns'
#copyfile =  'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\71mtp'
filepath = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\72\\72sns'
copyfile =  'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\72mtp'
shutil.rmtree(copyfile)
os.mkdir(copyfile)
findFie(filepath)

def readFile():
    readFile = open('./jobname')
    i = 0
    for eachLine in readFile:
        i= i + 1
        #print(eachLine)
        NameFiles.append(eachLine.replace('\n',''))  #  去掉换行符

readFile()

#字符串比较

def doTheCompare():
    for x in NameFiles:
        print(x)
        for y in AllFiles:
            if x == y :
                copyFrom = os.path.join(filepath,x)
                copyTo = os.path.join(copyfile,x)
                shutil.copyfile(copyFrom,copyTo)
            else:
                pass
                #print ("file not find under sns process,thanks .please check with wumi.")

doTheCompare()