题目
数据
结果
解答
1.
select distinct(Exam.student_id) as STUDENT_ID,
Student.student_name as STUDENT_NAME
from Exam
join Student on Student.student_id = Exam.student_id
2.结果、撇去最高、最低分。
select distinct(Exam.student_id) as STUDENT_ID,
Student.student_name as STUDENT_NAME
from Exam
join Student on Student.student_id = Exam.student_id
where Exam.student_id not in
(select distinct(student_id) from Exam
where (exam_id,score) in(select exam_id,max(score) as score from exam group by exam_id) # 实验最高分
or
(exam_id,score) in(select exam_id,min(score) as score from exam group by exam_id) # 实验最低分
)
order by Exam.student_id asc;