原题网址：http://www.lintcode.com/zh-cn/problem/hex-conversion/
Given a decimal number n and an integer k, Convert decimal number n to base-k.
注意事项
1.0<=n<=2^31-1, 2<=k<=16
2.Each letter over 9 is indicated in uppercase
样例
Example 1:
Given n = 5, k = 2
return "101"
Example 2:
Given n = 30, k = 16
return "1E"
标签
1 class Solution {
2 public:
3 /**
4 * @param n: a decimal number
5 * @param k: a Integer represent base-k
6 * @return: a base-k number
7 */
8 string hexConversion(int n, int k) {
9 // write your code here
10 if (n==0)
11 {
12 return "0";
13 }
14
15 char ch[16]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};//定义为int数组也可以;
16 string result="";
17 int mod=0;
18 while(n!=0)
19 {
20 mod=n%k;
21 n=n/k;
22 result.push_back(ch[mod]);
23 }
24 reverse(result.begin(),result.end());
25 return result;
26 }
27 };
