python批量启动多线程
还未了解多线程的请查看博文 python3多线程趣味详解
python3多线程趣味详解 只是介绍了 python
多线程的使用,对于批量启动线程来说有些不适用,于是出现如下方法:
建立一个线程池,并将某个线程放入进去
threadpool = []
th = threading.Thread(target=func_name, args=func_args)
threadpool.append(th)
批量加入线程
for i in range(10):
th = threading.Thread(target=func_name, args=func_args)
threadpool.append(th)
批量开始线程
for th in threadpool:
th.start()
for th in threadpool:
threading.Thread.join(th)
实例如下:
#!/usr/bin/python3.4
# -*- coding: utf-8 -*-
import time
import threading
def matter1(music, test):
print test, music
# 假设每一首歌曲的时间是2秒
time.sleep(2)
if __name__ == '__main__':
# 设定我要听的歌为
musics = ["music1", "music2", "music3"]
test = "122678"
# 开始时间
start = time.time()
threadpool = []
for music in musics:
th = threading.Thread(target=matter1, args=(music, test))
threadpool.append(th)
for th in threadpool:
th.start()
for th in threadpool:
threading.Thread.join(th)
# 结束时间
end = time.time()
print("完成的时间为:" + str(end - start))
完成同时听三首歌线程,花费时间 2s
:
限制线程数量可以使用Semaphore
,实例如下:
#!/usr/bin/python3.4
# -*- coding: utf-8 -*-
import time
import threading
#添加一个计数器
s1=threading.Semaphore(2)
def matter1(music, test):
# 计数器获得锁
s1.acquire()
print(test, music)
# 假设每一首歌曲的时间是2秒
time.sleep(2)
# 计数器释放锁
s1.release()
if __name__ == '__main__':
# 设定我要听的歌为
musics = ["music1", "music2", "music3"]
test = "122678"
# 开始时间
start = time.time()
threadpool = []
for music in musics:
th = threading.Thread(target=matter1, args=(music, test))
threadpool.append(th)
for th in threadpool:
th.start()
for th in threadpool:
threading.Thread.join(th)
# 结束时间
end = time.time()
print("完成的时间为:" + str(end - start))
完成听前2首歌线程,花费时间 2s
:
听第3首歌花费 2s
,最后一共花费 4s
: