C - Mine Sweeper

https://vjudge.net/problem/HDU-6879

题意:

给定S,r,c

构造一个r行c列的阵列。

对于没有炸弹的位置的数值为位置附近8个位置炸弹总数

保证炸弹总数S

 

代码:

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<bitset>
#include<cassert>
#include<cctype>
#include<cmath>
#include<cstdlib>
#include<ctime>
#include<deque>
#include<iomanip>
#include<list>
#include<map>
#include<queue>
#include<set>
#include<stack>
#include<vector>
#include <vector>
#include <iterator>
#include <utility>
#include <sstream>
#include <limits>
#include <numeric>
#include <functional>
using namespace std;
#define gc getchar()
#define mem(a) memset(a,0,sizeof(a))
#define debug(x) cout<<"debug:"<<#x<<" = "<<x<<endl;

#define ios ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);

typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int,int> pii;
typedef char ch;
typedef double db;

const double PI=acos(-1.0);
const double eps=1e-6;
const int inf=0x3f3f3f3f;
const int maxn=1e5+10;
const int maxm=100+10;
const int N=1e6+10;
const int mod=1e9+7;


const int dir[8][2] = {1, 0, 0, 1, -1, 0, 0, -1, -1, -1, -1, 1, 1, -1, 1, 1};
map< int, vector< vector<char> > > M;
int n = 0;
int main()
{
    srand((int) time(0));
    int T = 0;
    cin >> T;
    int random = 0;
    int chg = 0;
    
    for (int I = 1; I<=50000;I++)
	{
        random = (rand() % 25) + 1;
        chg = (rand() % 25) + 1;
        vector< vector<char> > A(random, vector<char>(chg));
        for(int i = 0;i<random;i++)
		{
            for(int j = 0;j<chg;j++)
			{
				if((rand()%2))
				{
					A[i][j] = 'X';
				}
				else
				{
					A[i][j] = '.';
				}
                
            }
        }
        random = A.size();
	    chg = A[0].size();
	    int S = 0;
	    for(int i = 0;i<random;i++)
		{
	        for(int j = 0;j<chg;j++)
			{
	            if (A[i][j] == '.')
				{
	                int counter = 0;
	                for (int L = 0;L<8;L++)
					{
	                    int dx = i + dir[L][0];
	                    int dy = j + dir[L][1];
	                    if ( (dx >= 0 && dx <= random-1) && (dy >= 0 && dy <= chg-1) )
						{
							if(A[dx][dy] == 'X')
							{
								counter++;
							}
	                    }
	                }
	                S += counter;
	            }
	        }
	    }
        M[S] = A;
    }

    while(T--)
	{
        cin >> n;
        vector< vector<char> > A = M[n];

        random = A.size();
        chg = A[0].size();
        cout << random << " " << chg << endl;
        for (int i = 0;i<random;i++)
		{
            for (int j = 0;j<chg;j++)
			{
                cout << A[i][j];
                if(j == chg - 1) cout << endl;
            }
        }
    }
    return 0;
}

  

posted @ 2020-08-25 21:47  YukiRinLL  阅读(87)  评论(0编辑  收藏  举报